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# At a contest with 1,500 participants, 1/2 of the people are aged 8 to

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Manager
Joined: 28 Jan 2011
Posts: 76
Location: Tennessee
Schools: Belmont University
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Kudos [?]: 170 [0], given: 73

At a contest with 1,500 participants, 1/2 of the people are aged 8 to [#permalink]

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07 Apr 2011, 14:20
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75% (01:41) correct 25% (00:28) wrong based on 8 sessions

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At a contest with 1,500 participants, 1/2 of the people are aged 8 to 12. Next year, the number of people aged 8 to 12 will increase by 1/3. After this change, what percentage of the total 1,500 people will the 8- to 12-year-olds represent?

A. 33%
B. 40%
C. 50%
D. 55%
E. 66 2/3%
[Reveal] Spoiler: OA
Manager
Joined: 28 Jan 2011
Posts: 76
Location: Tennessee
Schools: Belmont University
Followers: 2

Kudos [?]: 170 [0], given: 73

Re: At a contest with 1,500 participants, 1/2 of the people are aged 8 to [#permalink]

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07 Apr 2011, 14:24
Shalom Moderators
Pardon me for posting this question in the wrong forum. I will remember to post in the correct forum the next time.
Math Forum Moderator
Joined: 20 Dec 2010
Posts: 2013
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Kudos [?]: 1822 [0], given: 376

Re: At a contest with 1,500 participants, 1/2 of the people are aged 8 to [#permalink]

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07 Apr 2011, 14:56
MitDavidDv wrote:
At a contest with 1,500 participants, 1/2 of the people are aged 8 to 12. Next year, the number of people aged 8 to 12 will increase by 1/3. After this change, what percentage of the total 1,500 people will the 8- to 12-year-olds represent?

A. 33%
B. 40%
C. 50%
D. 55%
E. 66 2/3%

Currently half the participants are between 8 and 12

1/2*1500 = 750 participants

Next year this number will increase by 1/3

The number of participants between 8 and 12 years will be = 750+(1/3)*750 = (4/3)*750

(4/3)*750 is what percentage of 1500

$$\frac{4}{3}*750*\frac{1}{1500}*100$$

$$\frac{4}{3}*\frac{1}{2}*100 = \frac{200}{3} = 66\frac{2}{3}$$

Ans: "E"
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Kudos [?]: 533 [0], given: 36

Re: At a contest with 1,500 participants, 1/2 of the people are aged 8 to [#permalink]

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07 Apr 2011, 21:21
750 -> Aged 8 - 12

Next year -> 750 + 750/3 = 750 + 250 = 1000

So %age = 1000/1500 = 10/15 = 662/3 %

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Kudos [?]: 1603 [1] , given: 4

Re: At a contest with 1,500 participants, 1/2 of the people are aged 8 to [#permalink]

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08 Apr 2011, 06:51
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Expert's post
MitDavidDv wrote:
At a contest with 1,500 participants, 1/2 of the people are aged 8 to 12. Next year, the number of people aged 8 to 12 will increase by 1/3. After this change, what percentage of the total 1,500 people will the 8- to 12-year-olds represent?

A. 33%
B. 40%
C. 50%
D. 55%
E. 66 2/3%

I just wanted to mention a couple of things here:

* this is a pure ratio question; the number 1,500 is completely irrelevant, and you can ignore it if you like. When we increase something by 1/3, we are multiplying it by 1 + 1/3 = 4/3, so the answer here must be (1/2)*(4/3) = 2/3 = 66 2/3 %.

* you can certainly take advantage of the answer choices to get the answer without any computation. The fraction of 8-12 year olds has clearly increased, so D and E are the only candidates. D would be the answer if the increase were 10%; it's more than 10% so the answer must be E.
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Manager
Joined: 28 Jan 2011
Posts: 76
Location: Tennessee
Schools: Belmont University
Followers: 2

Kudos [?]: 170 [0], given: 73

Re: At a contest with 1,500 participants, 1/2 of the people are aged 8 to [#permalink]

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16 Apr 2011, 12:56
Shalom!
I am currently working on my GMAT preparation @ Belmont University.
Re: At a contest with 1,500 participants, 1/2 of the people are aged 8 to   [#permalink] 16 Apr 2011, 12:56
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