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At a fast food restaurant, Anas normally works 6.25 hours per day and

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At a fast food restaurant, Anas normally works 6.25 hours per day and  [#permalink]

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New post 28 Sep 2017, 01:39
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Question Stats:

86% (01:25) correct 14% (01:45) wrong based on 59 sessions

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At a fast food restaurant, Anas normally works 6.25 hours per day and earns $5.60 per hour. For each hour he works in excess of 6.25 hours on a given day, he is paid 1.25 times his regular rate. If Anas works 10.25 hours on a given day, how much does he earn for that day?

A. $72
B. $63
C. $54
D. $48
E. $35

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Re: At a fast food restaurant, Anas normally works 6.25 hours per day and  [#permalink]

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New post 28 Sep 2017, 01:49
At a fast food restaurant, Anas normally works 6.25 hours per day and earns $5.60 per hour. For each hour he works in excess of 6.25 hours on a given day, he is paid 1.25 times his regular rate. If Anas works 10.25 hours on a given day, how much does he earn for that day?

work = 6.25 hours
salary per hour = $5.60
Total salary earned = 6.25 * 5.60 = 35

For each extra hour, rate = 1.25 * 5.60 = 7

Now total hours works = 10.25 = 6.25 + 4
So got salary at rate of 5.60/hour for initial 6.25 hours and at rate of 7/hour for last 4 hours.

Total salary = (6.25*5.6) +(4*7) = 35+28 = $63

Answer: B
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At a fast food restaurant, Anas normally works 6.25 hours per day and  [#permalink]

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New post 28 Sep 2017, 12:30
Bunuel wrote:
At a fast food restaurant, Anas normally works 6.25 hours per day and earns $5.60 per hour. For each hour he works in excess of 6.25 hours on a given day, he is paid 1.25 times his regular rate. If Anas works 10.25 hours on a given day, how much does he earn for that day?

A. $72
B. $63
C. $54
D. $48
E. $35

Changing every decimal into a fraction makes arithmetic easier. Factors cancel.

Regular hours for a workday = 6.25 hrs =
\(6\frac{1}{4} = \frac{25}{4}\) hours

Regular pay: $5.60 per hr =
\(5\frac{3}{5} = \frac{$28}{5}\) per hour

Overtime: working > 6.25 hrs

Overtime rate of pay:
1.25 times regular rate =
\(1\frac{1}{4} = \frac{5}{4} * \frac{$28}{5} = \frac{$28}{4} = $7\) per hour

If Anas works 10.25 hours, how much does he earn for that day?

Extra hours worked: 10.25 - 6.25 =
4 extra hours

Earnings for extra hrs=
(Overtime rate) * (# of hours)
\((\frac{$7}{hr}) * (4 hrs) = $28\)

Earnings for regular hours =
(Regular rate) * (Regular # of hrs)
\(\frac{$28}{5hrs} * \frac{25}{4}hrs = $35\)

TOTAL earnings: $28 + $35 = $63

ANSWER B
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Re: At a fast food restaurant, Anas normally works 6.25 hours per day and  [#permalink]

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New post 03 Oct 2017, 10:04
Bunuel wrote:
At a fast food restaurant, Anas normally works 6.25 hours per day and earns $5.60 per hour. For each hour he works in excess of 6.25 hours on a given day, he is paid 1.25 times his regular rate. If Anas works 10.25 hours on a given day, how much does he earn for that day?

A. $72
B. $63
C. $54
D. $48
E. $35


Anas’ regular rate is $5.60 and his overtime rate is (1.25)(5.60), or $7. We can create the following equation:

6.25(5.6) + 4(1.25 x 5.6)

35 + 4(7) = 35 + 28 = 63

Answer: B
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Re: At a fast food restaurant, Anas normally works 6.25 hours per day and &nbs [#permalink] 03 Oct 2017, 10:04
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