At a local coffee shop, pastries may have nuts, chocolate, both, or ne

So basically there are four kinds of pastries: (1) having Only Chocolate, (2) having both Chocolate/Nuts, (3) having Only Nuts, (4) having Neither. We have to determine the number of type (3) pastries, i.e., having Only Nuts. And we know that (1) + (2) + (3) + (4) = 400

We are given that out of 400, 60% or 0.6*400 = 240 contain chocolates. So these 240 are sum of type (1) and (2). So we just need to know (4) to calculate the value of (3).

Statement 1 - gives us the number of type (4) pastries. these are 1/4 * 240 = 60. So we can find type (3). Sufficient.

Statement 2 - tells us that type (2) are 1/3 of type (1). But this is not sufficient to calculate type (3).

Hence A answer