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At a speed of 50 miles per hour, a certain car uses 1 gallon of

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Joined: 31 Jul 2017
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WE: Consulting (Energy and Utilities)
Re: At a speed of 50 miles per hour, a certain car uses 1 gallon of [#permalink]

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New post 31 Jan 2018, 20:28
TomB wrote:
At a speed of 50 miles per hour, a certain car uses 1 gallon of gasoline every 30 miles. If the car starts with a full 12 gallon tank of gasoline and travels for 5 hours at 50 miles per hour, the amount of gasoline used would be what fraction of a full tank?

A. 3/25
B. 11/36
C. 7/12
D. 2/3
E. 25/36

I am getting 2/3 .Please explain what am i missing?


Total Distance covered in 5 hours = 250 miles.
1 Gallon consumed every 30 miles. For 250 miles, the total gallon consumbed would be \(\frac{25}{3}\)
Total capacity = 12 Gallon.
Hence, \(25/36\).
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Re: At a speed of 50 miles per hour, a certain car uses 1 gallon of [#permalink]

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New post 31 Jan 2018, 20:59
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OCDianaOC wrote:
Bunuel wrote:
At a speed of 50 miles per hour, a certain car uses 1 gallon of gasoline every 30 miles. If the car starts with a full 12 gallon tank of gasoline and travels for 5 hours at 50 miles per hour, the amount of gasoline used would be what fraction of a full tank?

A. 3/25
B. 11/36
C. 7/12
D. 2/3
E. 25/36

In 5 hours at 50 miles per hour car will travel 5*50=250 miles and thus will use 250/30=25/3 gallons of gasoline. Gasoline used/full tank equals to \(\frac{(\frac{25}{3})}{12} =\frac{25}{36}\).

Answer: E.


I solved the problem with the approach below and got the correct answer. Did I just get lucky? Will this not work on another similar problem?

R x T = D
50mph x 5 hrs = 250 miles

12 gallons x 30 miles = 360 miles (since a car gets 1 gallon of gasoline for every 30 miles).

I then just took 250 miles and divided by 360 miles then reduced down to 25/36.


That's also a correct way to solve the problem.
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Re: At a speed of 50 miles per hour, a certain car uses 1 gallon of   [#permalink] 31 Jan 2018, 20:59

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