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At a speed of 50 miles per hour, a certain car uses 1 gallon of

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kilukilam
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At a speed of 50 miles per hour, a certain car uses 1 gallon [#permalink] New post   Updated on: 09 Feb 2012, 14:18
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At a speed of 50 miles per hour, a certain car uses 1 gallon of gasoline every 30 miles. If the car starts with a full 12 gallon tank of gasoline and travels for 5 hours at 50 miles per hour, the amount of gasoline used would be what fraction of a full tank?

A. 3/25
B. 11/36
C. 7/12
D. 2/3
E. 25/36
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E

Originally posted by kilukilam on 27 Jul 2010, 13:31.
Last edited by Bunuel on 09 Feb 2012, 14:18, edited 2 times in total.
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Re: At a speed of 50 miles per hour, a certain car uses 1 gallon of [#permalink] New post   23 Sep 2010, 14:39
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At a speed of 50 miles per hour, a certain car uses 1 gallon of gasoline every 30 miles. If the car starts with a full 12 gallon tank of gasoline and travels for 5 hours at 50 miles per hour, the amount of gasoline used would be what fraction of a full tank?

A. 3/25
B. 11/36
C. 7/12
D. 2/3
E. 25/36

In 5 hours at 50 miles per hour car will travel 5*50=250 miles and thus will use 250/30=25/3 gallons of gasoline. Gasoline used/full tank equals to \(\frac{(\frac{25}{3})}{12} =\frac{25}{36}\).

Answer: E.
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At a speed of 50 miles per hour, a certain car uses 1 gallon of [#permalink] New post   27 Jul 2010, 14:28
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16. Distance/Rate Problems



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Re: At a speed of 50 miles per hour, a certain car uses 1 gallon of [#permalink] New post   29 Dec 2010, 07:53
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In the given example SPEED is not mentioned with which the car traveled for 5 hrs with 12 gallons in the tank

Therefore, we have to assume that car traveled with the same speed

Now we can calculate distance traveled by the car in 5 hrs = D = S*t
= 50 * 5 = 250 miles

We know that car travels 30 miles in 1 gallon
Therefore gallons of fuel required for 250 miles = 25/3

Hence, fraction of fuel used = 25 /3*12 = 25 / 36

But according to me something is missed out in the question, because, mostly in GMAT answers are not awkward like this.
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Re: world problem [#permalink] New post   28 Oct 2011, 16:12
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My approach:

\(? Gal=5 hours*\frac{50 miles}{1 hour}*\frac{1 Gal}{30 miles}=\frac{25}{3}\)

We write the above equation while we are saying this: How many Gallon we need for 5 hours, while we know that in every 1 hour we go 50 miles, and we know that for every 30 miles we consume 1 Gallon.


and the fraction of used to total:\(\frac{\frac{25}{3}}{12}=\frac{25}{36}\)
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Re: At a speed of 50 miles per hour, a certain car uses 1 gallon [#permalink] New post   22 Aug 2012, 00:23
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I did the problem differently. Is this a solid approach?


5 hours at 50 MPH, the car will travel 5*50=250 miles

Total capacity of the tank is 12 gallons. At 50 MPH, the car uses 30 miles per gallon.

30*12 = 360 gallons total

\(\frac{250 miles driven}{360 miles tank} = \frac{25}{36}\)
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Re: At a speed of 50 miles per hour, a certain car uses 1 gallon [#permalink] New post   22 Aug 2012, 01:13
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bmwguy wrote:
I did the problem differently. Is this a solid approach?


5 hours at 50 MPH, the car will travel 5*50=250 miles

Total capacity of the tank is 12 gallons. At 50 MPH, the car uses 30 miles per gallon.

30*12 = 360 gallons total

\(\frac{250 miles driven}{360 miles tank} = \frac{25}{36}\)


The answer is correct but the reasoning is not.

We are told that the car uses 1 gallon of gasoline every 30 miles, so 12 gallons (full tank) of gasoline is enough to travel 12*30=360 miles. Since the car traveled only 250 miles, then it used 250/360=25/36 of full tank.

Hope it's clear.
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Re: At a speed of 50 miles per hour, a certain car uses 1 gallon [#permalink] New post   27 Mar 2015, 07:56
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5 hours of driving @ 50 miles an hour; 250 total miles
1 liter per 30 miles; 250/30 = 8 1/3
8 1/3 x 3 = 25
12 x 3 = 36

25/36. E.
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Re: At a speed of 50 miles per hour, a certain car uses 1 gallon [#permalink] New post   25 Oct 2016, 17:02
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kilukilam wrote:
At a speed of 50 miles per hour, a certain car uses 1 gallon of gasoline every 30 miles. If the car starts with a full 12 gallon tank of gasoline and travels for 5 hours at 50 miles per hour, the amount of gasoline used would be what fraction of a full tank?

A. 3/25
B. 11/36
C. 7/12
D. 2/3
E. 25/36


We are given that a certain car has a rate of 30 miles per gallon. We are next told that the car starts with a 12-gallon tank and travels for 5 hours at 50 miles per hour.

Since distance = rate x time, we know the car traveled 50 x 5 = 250 miles. We can use the car’s rate and distance traveled to determine how many gallons were used.

Gallons used = distance/rate

Gallons used = 250/30 = 25/3

Finally, we need to determine the amount of gasoline used as a fraction of a full 12-gallon tank.

(25/3)/12 = (25/3) x (1/12) = 25/36

Answer: E
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Re: At a speed of 50 miles per hour, a certain car uses 1 gallon of [#permalink] New post   30 May 2017, 17:26
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TomB wrote:
At a speed of 50 miles per hour, a certain car uses 1 gallon of gasoline every 30 miles. If the car starts with a full 12 gallon tank of gasoline and travels for 5 hours at 50 miles per hour, the amount of gasoline used would be what fraction of a full tank?

A. 3/25
B. 11/36
C. 7/12
D. 2/3
E. 25/36

I am getting 2/3 .Please explain what am i missing?

1.In 5 hrs the car would have traveled 250 miles.
2. It would have used 250/30 gallons
3. The car started with full tank of 12 gallons
4. Gasoline used as a fraction of full tank is (250/30)/12=25/36
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Re: At a speed of 50 miles per hour, a certain car uses 1 gallon of [#permalink] New post   13 Aug 2018, 07:57
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TomB wrote:
At a speed of 50 miles per hour, a certain car uses 1 gallon of gasoline every 30 miles. If the car starts with a full 12 gallon tank of gasoline and travels for 5 hours at 50 miles per hour, the amount of gasoline used would be what fraction of a full tank?

A. 3/25
B. 11/36
C. 7/12
D. 2/3
E. 25/36


At a speed of 50 miles per hour, a certain car uses 1 gallon of gasoline every 30 miles.
Time = distance/speed
So, time to travel 30 miles = 30/50 = 3/5 hours.
This means that the car uses 1 gallon for every 3/5 hours.

Let x = the number of gallons of gas used during the 5 hour trip.

We get the following equivalent ratios: 1/(3/5) = x/ 5
Cross multiply to get: 5 = (3/5)x
Multiply both sides by 5/3 to get: 25/3 = x
So, the car uses 25/3 gallons of gas

The amount of gasoline used would be what fraction of a full tank?
We get (25/3)/12, which equals 25/36

Answer: E

Cheers,
Brent
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Re: At a speed of 50 miles per hour, a certain car uses 1 gallon of [#permalink] New post   22 Jul 2020, 22:28
Bunuel wrote:
bmwguy wrote:
I did the problem differently. Is this a solid approach?


5 hours at 50 MPH, the car will travel 5*50=250 miles

Total capacity of the tank is 12 gallons. At 50 MPH, the car uses 30 miles per gallon.

30*12 = 360 gallons total

\(\frac{250 miles driven}{360 miles tank} = \frac{25}{36}\)


The answer is correct but the reasoning is not.

We are told that the car uses 1 gallon of gasoline every 30 miles, so 12 gallons (full tank) of gasoline is enough to travel 12*30=360 miles. Since the car traveled only 250 miles, then it used 250/360=25/36 of full tank.

Hope it's clear.



I did it in another way, but I'm not sure if I did it right.

the car spends 1 gallon every 30m, so 2g every 1h, the problem says the drove for 5h(that mean 10g of fuel consume)
now we are told the full tank is 12g.
now we have what we spent over what we had: 10/12= 5/6 (but i don't have this option but the same with option E, multiplying each side by the same number.

can anyone help me out to know if i'm right doing this proble, Bunuel please.
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Re: At a speed of 50 miles per hour, a certain car uses 1 gallon of [#permalink] New post   22 Jul 2020, 22:58
Alvarito wrote:
Bunuel wrote:
bmwguy wrote:
I did the problem differently. Is this a solid approach?


5 hours at 50 MPH, the car will travel 5*50=250 miles

Total capacity of the tank is 12 gallons. At 50 MPH, the car uses 30 miles per gallon.

30*12 = 360 gallons total

\(\frac{250 miles driven}{360 miles tank} = \frac{25}{36}\)


The answer is correct but the reasoning is not.

We are told that the car uses 1 gallon of gasoline every 30 miles, so 12 gallons (full tank) of gasoline is enough to travel 12*30=360 miles. Since the car traveled only 250 miles, then it used 250/360=25/36 of full tank.

Hope it's clear.



I did it in another way, but I'm not sure if I did it right.

the car spends 1 gallon every 30m, so 2g every 1h, the problem says the drove for 5h(that mean 10g of fuel consume)
now we are told the full tank is 12g.
now we have what we spent over what we had: 10/12= 5/6 (but i don't have this option but the same with option E, multiplying each side by the same number.

can anyone help me out to know if i'm right doing this proble, Bunuel please.

He travel 50 miles an hour using 1 gallon per 30 miles.
Taking LCM of 30&50 = 150
That means he will use 5 gallon for 3 hour drive.
Or 1.666 gallon for 1 hour.
For 5 hours he will use 5*1.66 gallon = 8.33 gallons

Which is 8.33/12 gallon of total
Or 25/36 gallon of total.

You can't round figure 1.66 to 2 gallon an hour. It will create a serious gap between usage and consumption.

Posted from my mobile device
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Re: At a speed of 50 miles per hour, a certain car uses 1 gallon of [#permalink] New post   23 Jul 2020, 22:34
yashikaaggarwal wrote:
Alvarito wrote:
Bunuel wrote:
bmwguy wrote:
I did the problem differently. Is this a solid approach?


5 hours at 50 MPH, the car will travel 5*50=250 miles

Total capacity of the tank is 12 gallons. At 50 MPH, the car uses 30 miles per gallon.

30*12 = 360 gallons total

\(\frac{250 miles driven}{360 miles tank} = \frac{25}{36}\)


The answer is correct but the reasoning is not.

We are told that the car uses 1 gallon of gasoline every 30 miles, so 12 gallons (full tank) of gasoline is enough to travel 12*30=360 miles. Since the car traveled only 250 miles, then it used 250/360=25/36 of full tank.

Hope it's clear.



I did it in another way, but I'm not sure if I did it right.

the car spends 1 gallon every 30m, so 2g every 1h, the problem says the drove for 5h(that mean 10g of fuel consume)
now we are told the full tank is 12g.
now we have what we spent over what we had: 10/12= 5/6 (but i don't have this option but the same with option E, multiplying each side by the same number.

can anyone help me out to know if i'm right doing this proble, Bunuel please.

He travel 50 miles an hour using 1 gallon per 30 miles.
Taking LCM of 30&50 = 150
That means he will use 5 gallon for 3 hour drive.
Or 1.666 gallon for 1 hour.
For 5 hours he will use 5*1.66 gallon = 8.33 gallons

Which is 8.33/12 gallon of total
Or 25/36 gallon of total.

You can't round figure 1.66 to 2 gallon an hour. It will create a serious gap between usage and consumption.

Posted from my mobile device


Thanks for the help. now i know what i did wrong, i read 30 minutes instead of 30 miles, he drive 5h for 50 miles per hour, spending 1gallon every 30 miles (i thought 1g every 30 minutes).

thanks for the help!
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Re: At a speed of 50 miles per hour, a certain car uses 1 gallon of [#permalink] New post   27 Mar 2024, 11:35
Sharing my experience in case it helps anyone...
I was rushing so when I got to 25/3 I write approx. 8. Then divided 8/12 and got 2/3... The question was not asking to approximate therefore I got it wrong. 2/3 is close to 25/36 but the exact answer choice and calculation takes us to 25/36.
Nice to keep in mind...
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At a speed of 50 miles per hour, a certain car uses 1 gallon of [#permalink] New post   31 Mar 2024, 00:11
Ans (E)

Speed of the car = 50 mph

Gasoline consumption in miles per gallon = 30 miles/gallon

Gasoline consumption per hour = \(\frac{Speed \ of \ the \ car \ (miles \ per \ hour)}{Gasoline \ consumption \ (miles \ per \ gallon)}\) = \(\frac{50}{30}\) = \(\frac{5}{3}\) gallons/hour

That means every hour, the car is consuming \(\frac{5}{3}\) gallons.

Further, it has been given that the car has been travelling for 5 hours, which means it would have consumed = \(\frac{5}{3}*5\) = \(\frac{25}{3}\) gallons

Therefore, gasoline consumed after 5 hours per fraction of 12 gallon fuel tank = \(\frac{25}{3}*\frac{1}{12}\) = \(\frac{25}{36}\)
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