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At a supermarket, John spent 1/2 of his money on fresh fruits and vegetables, 1/3 on meat products, and 1/10 on bakery products. If he spent the remaining $6 on candy, how much did John spend at the supermarket?

(A) $60 (B) $80 (C) $90 (D) $120 (E) $180

Practice Questions Question: 15 Page: 154 Difficulty: 600

WE 1: 7 Yrs in Automobile (Commercial Vehicle industry)

Re: At a supermarket, John spent 1/2 of his money on fresh fruit [#permalink]

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06 Aug 2012, 06:06

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x/2+x/3+x/10 = 28x/30

2x/30=6, hence x =90 Ans C.
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At a supermarket, John spent 1/2 of his money on fresh fruits and vegetables, 1/3 on meat products, and 1/10 on bakery products. If he spent the remaining $6 on candy, how much did John spend at the supermarket?

(A) $60 (B) $80 (C) $90 (D) $120 (E) $180

John spent \(1-(\frac{1}{2}+\frac{1}{3}+\frac{1}{10})=\frac{1}{15}\) of his money on candy. Since we are told that he spent $6 on candy, then he spent total of \($6*15=90\) at the supermarket.

Re: At a supermarket, John spent 1/2 of his money on fresh fruit [#permalink]

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26 Dec 2013, 02:11

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mandrake15 wrote:

Bunuel wrote:

SOLUTION

At a supermarket, John spent 1/2 of his money on fresh fruits and vegetables, 1/3 on meat products, and 1/10 on bakery products. If he spent the remaining $6 on candy, how much did John spend at the supermarket?

(A) $60 (B) $80 (C) $90 (D) $120 (E) $180

John spent \(1-(\frac{1}{2}+\frac{1}{3}+\frac{1}{10})=\frac{1}{15}\) of his money on candy. Since we are told that he spent $6 on candy, then he spent total of \($6*15=90\) at the supermarket.

Answer: C.

Hello, i don't understand the part of "$6*15=90" can you explain me please? Why 6 its multiplied by 15?

Hello, as Bunuel explained above, John spent 1/15 of his money (remaining of his money) on candy ==> The remaining = 1/15 of his money = $6 ==> total money spent = 15/15 of the remaining = 15*6 = 90

Hope it's clear.
_________________

Please +1 KUDO if my post helps. Thank you.

"Designing cars consumes you; it has a hold on your spirit which is incredibly powerful. It's not something you can do part time, you have do it with all your heart and soul or you're going to get it wrong."

At a supermarket, John spent 1/2 of his money on fresh fruits and vegetables, 1/3 on meat products, and 1/10 on bakery products. If he spent the remaining $6 on candy, how much did John spend at the supermarket?

(A) $60 (B) $80 (C) $90 (D) $120 (E) $180

John spent \(1-(\frac{1}{2}+\frac{1}{3}+\frac{1}{10})=\frac{1}{15}\) of his money on candy. Since we are told that he spent $6 on candy, then he spent total of \($6*15=90\) at the supermarket.

Re: At a supermarket, John spent 1/2 of his money on fresh fruit [#permalink]

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15 Jun 2013, 03:43

1

This post received KUDOS

Simply pick number from answer...

80 will be out since not divisible by 3.

Lets try 90..according to question 1/2 of 90= 45, 1/3 of 90=30 and 1/10 of 90=9 then just add all of them i.e 45+30+9=84. Now 90-84=6 left for candy hence 90 will be the answer..

Re: At a supermarket, John spent 1/2 of his money on fresh fruit [#permalink]

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23 Dec 2013, 11:15

1

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Bunuel wrote:

SOLUTION

At a supermarket, John spent 1/2 of his money on fresh fruits and vegetables, 1/3 on meat products, and 1/10 on bakery products. If he spent the remaining $6 on candy, how much did John spend at the supermarket?

(A) $60 (B) $80 (C) $90 (D) $120 (E) $180

John spent \(1-(\frac{1}{2}+\frac{1}{3}+\frac{1}{10})=\frac{1}{15}\) of his money on candy. Since we are told that he spent $6 on candy, then he spent total of \($6*15=90\) at the supermarket.

Answer: C.

Hello, i don't understand the part of "$6*15=90" can you explain me please? Why 6 its multiplied by 15?

At a supermarket, John spent 1/2 of his money on fresh fruits and vegetables, 1/3 on meat products, and 1/10 on bakery products. If he spent the remaining $6 on candy, how much did John spend at the supermarket?

(A) $60 (B) $80 (C) $90 (D) $120 (E) $180

Solution:

Let's let T = total number of dollars spent at the supermarket. With this variable we can set up an equation and determine T.

We are given that John spent 1/2 of his money on fresh fruits and vegetables, or (1/2)T, 1/3 on meat products, or (1/3)T, and 1/10 on bakery products, or (1/10)T. We are also given that he spent the remaining $6 on candy. Since we know where all his money was allocated, we can sum these values together and set the sum to T. So we have:

(1/2)T + (1/3)T + (1/10)T + 6 = T

To get rid of the fractions we can multiply the entire equation by 30, and we obtain:

15T + 10T + 3T + 180 = 30T

28T + 180 = 30T

180 = 2T

T = 90

John spent $90 at the supermarket.

Answer: C
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GMAT Quant Self-Study Course 500+ lessons 3000+ practice problems 800+ HD solutions

Re: At a supermarket, John spent 1/2 of his money on fresh fruit [#permalink]

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09 Sep 2014, 23:06

Bunuel wrote:

At a supermarket, John spent 1/2 of his money on fresh fruits and vegetables, 1/3 on meat products, and 1/10 on bakery products. If he spent the remaining $6 on candy, how much did John spend at the supermarket?

(A) $60 (B) $80 (C) $90 (D) $120 (E) $180

Practice Questions Question: 15 Page: 154 Difficulty: 600

Re: At a supermarket, John spent 1/2 of his money on fresh fruit [#permalink]

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20 May 2016, 11:08

Bunuel wrote:

At a supermarket, John spent 1/2 of his money on fresh fruits and vegetables, 1/3 on meat products, and 1/10 on bakery products. If he spent the remaining $6 on candy, how much did John spend at the supermarket?

(A) $60 (B) $80 (C) $90 (D) $120 (E) $180

Practice Questions Question: 15 Page: 154 Difficulty: 600

Let total amount be 60x

Money spent on fresh fruits and vegetables = 30x Money spent on meat products = 20x Money spent on bakery products = 6x

Total money spent 56x

Money left (4x) = 6

So, x = 1.5

So, total money John had initially is 1.5 x 60 => $90

Hence answer will be $90 _________________

Thanks and Regards

Abhishek....

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