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At a twocandidate election for mayor, 3/4 of the registered [#permalink]
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04 Sep 2011, 04:15
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84% (01:43) correct
16% (03:45) wrong based on 154 sessions
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At a twocandidate election for mayor, 3/4 of the registered voters cast ballots. How many registered voters cast ballots for the winning candidate? (1) 25000 registered voters did not cast ballots in the election. (2) Of the registered voters who cast ballots, 55 percent cast ballots for the winning candidate
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Last edited by Bunuel on 04 Jul 2013, 06:57, edited 1 time in total.
Renamed the topic, edited the question and added the OA.



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Re: Election!! [#permalink]
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04 Sep 2011, 04:33
At a two candidate election for mayor, 3/4 of the voters cast ballots. How many registered voters cast ballot for the winning candidate? 1) 25000 registered voters didnot cast ballots in the election. 2) Of the registered voters who cast ballots, 55% cast ballots for the winning candidate. Option A : 3/4 voters cast their ballots..that means 1/4 didnt. By option 1, we get 1/4 (x) = 25,000. But no idea of how many people cast their ballot for the winning team. Hence, insufficient Option B : 55% cast thier ballot. No idea how many ballots were cast. Hence, insufficient. Taking A nd B together, we know that how many ppl casted their ballot(from A) and out of the total ballot casted, how many in favour of the winning candidate(option b). Hence, IMO C
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Re: Election!! [#permalink]
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04 Sep 2011, 04:45
Statement 1: tells us that 25,000 constitute the 1/4 of voters who did not cast vote. And hence if 1/4 =25000 then total equal to 1Lakh.But it does not alone help in solving the question. Statement 2: tells that that 55%(3/4*total voters who cast vote) had voted for the winner, but it does not solve the question alone.
Combining both the statements. We now that 55% of 75,000( 3/4*1lakh) cast vote for winning candidate and hence solving the question.
Hence C.



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Re: Election!! [#permalink]
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15 Sep 2011, 16:50
(3V)/4  cast V/4  did not cast
# of reg voters who casted for winning candidate?
1. Not Sufficient 25k = V/4 Hence we can find V i.e total voters => we can find total cast.
But there is no way of knowing how many of this total cast voted for winning candidate.
2. Not Sufficient
(55/100)(3V/4)  number of voters who voted for winning candidate.
But we dont know V .
togeter its sufficient.
Answer is C.



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Re: Election!! [#permalink]
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15 Sep 2011, 18:19
DeeptiM wrote: At a two candidate election for mayor, 3/4 of the voters cast ballots. How many registered voters cast ballot for the winning candidate?
1) 25000 registered voters didnot cast ballots in the election. 2) Of the registered voters who cast ballots, 55% cast ballots for the winning candidate. According to the question stem, 3/4th of the voters cast ballots. Let the total no of voters = x (One thing which might be little confusing here is the use of word "registered". We might assume that voters may be of two types: registered and not registered  this assumption is not correct because common sense says that only people who are registered can vote (unless clearly stated in question otherwise). So here we will go by the common logic and assume that all the voters are registered)Now the question becomes a simpler one. Statement 1: from question stem we know that voters who cast ballots = 3/4x So, voters who did not cast ballots = 1/4x = 25000 Hence x = 100,000 But this statement does not give any information about the ballots for winning candidates. Hence INSUFFICIENTStatement 2: We can calculate the percentage of voters who cast for winning ballot but we can not find the absolute number. For that we need the number of registered voters. Hence INSUFFICIENTCombining statement 1 and 2: From statement 1, we have that the number of voters and from statement 2, we have the percentage of winning ballots. So, the numbers of registered voters who cast winning ballots = 75,000*55/100. SUFFICIENTAnswer is C
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Re: Election!! [#permalink]
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15 Sep 2011, 22:30
GMATPASSION wrote: +1 for C. This question has a logic flaw. It must mention that there can only be registered users. Otherwise the equation (1/4) X = 25000 IS NOT APPLICABLE.



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Re: Election!! [#permalink]
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17 Sep 2011, 11:48
My 2 Cents: The answer seems a straight forward C, but in my opinion the Non Registered Voters would come into the picture thus making the ans as E.



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Re: Election!! [#permalink]
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17 Sep 2011, 14:03
I also feel the answer should be E. Please tell what is the OA?
BR Mandeep



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Re: At a two candidate election for mayor, 3/4 of the voters [#permalink]
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04 Jul 2013, 05:17
is this a venn diagram question / double matrix? If it is how would set up the table?
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Re: At a two candidate election for mayor, 3/4 of the voters [#permalink]
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04 Jul 2013, 07:06
fozzzy wrote: is this a venn diagram question / double matrix? If it is how would set up the table? No it is not, because we do not have overlapping sets. We cannot have a voter who cast the ballot for both candidates. It's a simple word problem. At a twocandidate election for mayor, 3/4 of the registered voters cast ballots. How many registered voters cast ballots for the winning candidate?3/4 of the registered voters cast ballots and 1/4 of the registered voters did NOT cast ballots. (1) 25000 registered voters did not cast ballots in the election > 25,000 registered voters = 1/4 of the registered voters, thus there are total of 4*25,000=100,000 registered voters and 75,000 of them cast ballots. We don;t know how those people voted. Not sufficient. (2) Of the registered voters who cast ballots, 55 percent cast ballots for the winning candidate. We know only percentage. Not sufficient. (1)+(2) 0.55*75,000=41,250 registered voters cast ballots for the winning candidate. Sufficient. Answer: C. Hope it's clear.
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Re: At a twocandidate election for mayor, 3/4 of the registered [#permalink]
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Re: At a twocandidate election for mayor, 3/4 of the registered
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