Author 
Message 
TAGS:

Hide Tags

Manager
Joined: 02 Dec 2012
Posts: 178

At least 2/3 of the 40 members of a committee must vote in [#permalink]
Show Tags
05 Dec 2012, 08:05
3
This post received KUDOS
6
This post was BOOKMARKED
Question Stats:
75% (01:50) correct
25% (00:59) wrong based on 1083 sessions
HideShow timer Statistics
At least 2/3 of the 40 members of a committee must vote in favor of a resolution for it to pass. What is the greatest number of members who could vote against the resolution and still have it pass? (A) 19 (8) 17 (C) 16 (D) 14 (E) 13
Official Answer and Stats are available only to registered users. Register/ Login.



Math Expert
Joined: 02 Sep 2009
Posts: 39751

Re: At least 2/3 of the 40 members of a committee must vote in [#permalink]
Show Tags
05 Dec 2012, 08:10
3
This post received KUDOS
Expert's post
1
This post was BOOKMARKED



Director
Joined: 25 Apr 2012
Posts: 728
Location: India
GPA: 3.21
WE: Business Development (Other)

Re: At least 2/3 of the 40 members of a committee must vote in [#permalink]
Show Tags
29 Sep 2013, 00:12
1
This post received KUDOS
AasaanHai wrote: Bunuel wrote: Walkabout wrote: At least 2/3 of the 40 members of a committee must vote in favor of a resolution for it to pass. What is the greatest number of members who could vote against the resolution and still have it pass?
(A) 19 (8) 17 (C) 16 (D) 14 (E) 13 Since, at least 2/3 of the 40 members of a committee must vote in favor, then at least \(\frac{2}{3}*40=26\frac{2}{3}\) or at least 27 members should vote in favor. Therefore at most 13 members could vote against. Answer: E. What is wrong in the way I am doing this question? It is given that at least 2/3rd of the 40 members should vote for the resolution. Since the members have to be a positive integer, I have considered 40 as 39 and then divided it by 3. After calculation, 26 members should vote for resolution. The remaining are 14 members who can vote against it; I marked D, which is incorrect. Well you calculated for 39 members...How about the 1 that you left out....Since the Questions says At least 2/3 of 40 which is 26.666....Now atleast means it can be more and the least possible Integer value is 27....So most 13 members can vote against.
_________________
“If you can't fly then run, if you can't run then walk, if you can't walk then crawl, but whatever you do you have to keep moving forward.”



EMPOWERgmat Instructor
Status: GMAT Assassin/CoFounder
Affiliations: EMPOWERgmat
Joined: 19 Dec 2014
Posts: 9290
Location: United States (CA)
GRE 1: 340 Q170 V170

Re: At least 2/3 of the 40 members of a committee must vote in [#permalink]
Show Tags
30 Jan 2016, 10:59
Hi studentsensual, You seem to understand that you can't have a 'fraction of a person' in these types of questions. Thus, you have to pay attention to the question that is ASKED and think in terms of 'whole persons.' Here, we're told that AT LEAST 2/3 of the 40 members of a committee must vote in favor of a resolution for it to pass. Since 2/3 of 40 is 26.666666, but we can't have 26.666666 people, we have to round UP to 27. In contrast, 26 people would NOT be enough, since 26/40 = 13/20 = 65% (and not the 66 2/3% minimum that a resolution needs to be passed). Knowing that it would take AT LEAST 27 people to pass a resolution, the GREATEST number who could vote AGAINST the resolution in this case would be 4027 = 13. Final Answer: GMAT assassins aren't born, they're made, Rich
_________________
760+: Learn What GMAT Assassins Do to Score at the Highest Levels Contact Rich at: Rich.C@empowergmat.com
Rich Cohen
CoFounder & GMAT Assassin
***********************Select EMPOWERgmat Courses now include ALL 6 Official GMAC CATs!***********************



Manager
Joined: 01 Oct 2010
Posts: 82
Location: United States (NC)
GPA: 2.3
WE: Information Technology (Computer Software)

Re: At least 2/3 of the 40 members of a committee must vote in [#permalink]
Show Tags
28 Sep 2013, 23:32
Bunuel wrote: Walkabout wrote: At least 2/3 of the 40 members of a committee must vote in favor of a resolution for it to pass. What is the greatest number of members who could vote against the resolution and still have it pass?
(A) 19 (8) 17 (C) 16 (D) 14 (E) 13 Since, at least 2/3 of the 40 members of a committee must vote in favor, then at least \(\frac{2}{3}*40=26\frac{2}{3}\) or at least 27 members should vote in favor. Therefore at most 13 members could vote against. Answer: E. What is wrong in the way I am doing this question? It is given that at least 2/3rd of the 40 members should vote for the resolution. Since the members have to be a positive integer, I have considered 40 as 39 and then divided it by 3. After calculation, 26 members should vote for resolution. The remaining are 14 members who can vote against it; I marked D, which is incorrect.
_________________
 Consider to give me kudos if my post helped you.



Manager
Joined: 12 Jan 2013
Posts: 219

Re: At least 2/3 of the 40 members of a committee must vote in [#permalink]
Show Tags
19 Dec 2013, 02:38
Walkabout wrote: At least 2/3 of the 40 members of a committee must vote in favor of a resolution for it to pass. What is the greatest number of members who could vote against the resolution and still have it pass?
(A) 19 (8) 17 (C) 16 (D) 14 (E) 13 40/3 = 13.3 (approx).. > 13.3 x 2 = 26.6, so at least 27 people have to vote in favor for it to pass. > 13 at most can vote against for it to pass.



Manager
Joined: 12 Jan 2013
Posts: 219

Re: At least 2/3 of the 40 members of a committee must vote in [#permalink]
Show Tags
10 Jan 2014, 01:39
Walkabout wrote: At least 2/3 of the 40 members of a committee must vote in favor of a resolution for it to pass. What is the greatest number of members who could vote against the resolution and still have it pass?
(A) 19 (8) 17 (C) 16 (D) 14 (E) 13 Dividing 40/3 gives us 13.33333, thus 2/3 = 26.6666.. So in order for it to pass, at least 26.6 people need to vote on it, but of course we need an integer so at least 27 people need to vote on it (so, in practice, a bigger portion than 2/3).. That leaves us with 13 people that can vote against and still have it pass. The noninteger throws us off and in some cases makes us round down. I think that's what they primarily want to test us on in this case, if we understand that we should round UP for required votes instead of round down.



Intern
Joined: 19 Jan 2014
Posts: 31

Re: At least 2/3 of the 40 members of a committee must vote in [#permalink]
Show Tags
21 Feb 2014, 16:21
The way I calculated was. At least 2/3 so it's the minimum than the greatest portion we would have left would be 1/3. Hence (40x1)/3 13,3... = 13 people



GMAT Club Legend
Joined: 09 Sep 2013
Posts: 16024

Re: At least 2/3 of the 40 members of a committee must vote in [#permalink]
Show Tags
10 Mar 2015, 19:55
Hello from the GMAT Club BumpBot! Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up  doing my job. I think you may find it valuable (esp those replies with Kudos). Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
GMAT Books  GMAT Club Tests  Best Prices on GMAT Courses  GMAT Mobile App  Math Resources  Verbal Resources



Intern
Joined: 27 Oct 2015
Posts: 18

Re: At least 2/3 of the 40 members of a committee must vote in [#permalink]
Show Tags
26 Jan 2016, 22:59
2/3 of 40 which is 26.666, there is no 0.666 person, so I decided 2/3 of 40 is 26, thus 4026=14, at least means minimum, not maximum, so minimum possible numbers, then it's logical to consider 26, moreover question asks the greatest number of members, how could I realize wherther to round up or not? Thanks! WoundedTiger wrote: AasaanHai wrote: Bunuel wrote: Since, at least 2/3 of the 40 members of a committee must vote in favor, then at least \(\frac{2}{3}*40=26\frac{2}{3}\) or at least 27 members should vote in favor. Therefore at most 13 members could vote against.
Answer: E. What is wrong in the way I am doing this question? It is given that at least 2/3rd of the 40 members should vote for the resolution. Since the members have to be a positive integer, I have considered 40 as 39 and then divided it by 3. After calculation, 26 members should vote for resolution. The remaining are 14 members who can vote against it; I marked D, which is incorrect. Well you calculated for 39 members...How about the 1 that you left out....Since the Questions says At least 2/3 of 40 which is 26.666....Now atleast means it can be more and the least possible Integer value is 27....So most 13 members can vote against.



Intern
Joined: 27 Oct 2015
Posts: 18

Re: At least 2/3 of the 40 members of a committee must vote in [#permalink]
Show Tags
31 Jan 2016, 19:31
So, when dealing with individuals, should I every time to round the numbers up? Thanks! EMPOWERgmatRichC wrote: Hi studentsensual, You seem to understand that you can't have a 'fraction of a person' in these types of questions. Thus, you have to pay attention to the question that is ASKED and think in terms of 'whole persons.' Here, we're told that AT LEAST 2/3 of the 40 members of a committee must vote in favor of a resolution for it to pass. Since 2/3 of 40 is 26.666666, but we can't have 26.666666 people, we have to round UP to 27. In contrast, 26 people would NOT be enough, since 26/40 = 13/20 = 65% (and not the 66 2/3% minimum that a resolution needs to be passed). Knowing that it would take AT LEAST 27 people to pass a resolution, the GREATEST number who could vote AGAINST the resolution in this case would be 4027 = 13. Final Answer: GMAT assassins aren't born, they're made, Rich



EMPOWERgmat Instructor
Status: GMAT Assassin/CoFounder
Affiliations: EMPOWERgmat
Joined: 19 Dec 2014
Posts: 9290
Location: United States (CA)
GRE 1: 340 Q170 V170

Re: At least 2/3 of the 40 members of a committee must vote in [#permalink]
Show Tags
31 Jan 2016, 23:50
Hi studentsensual, If a question expects you to 'round up' or 'round down', then you have to make sure to choose the answer that focuses on the specifics of the given prompt and answers the question that is asked: Here, the specific information stated that AT LEAST 2/3 (meaning at least 66 2/3%) of the members must vote in favor of a resolution for it to pass. Since 26/40 is only 65%, then 26 people would NOT be enough. Thus, you have to round that number UP to 27 (because that's what the question requires). There could conceivably be questions that would require you to round down, but that's not what THIS question required. GMAT assassins aren't born, they're made, Rich
_________________
760+: Learn What GMAT Assassins Do to Score at the Highest Levels Contact Rich at: Rich.C@empowergmat.com
Rich Cohen
CoFounder & GMAT Assassin
***********************Select EMPOWERgmat Courses now include ALL 6 Official GMAC CATs!***********************



Intern
Joined: 27 Oct 2015
Posts: 18

Re: At least 2/3 of the 40 members of a committee must vote in [#permalink]
Show Tags
04 Feb 2016, 06:00
Please compare these questions: At least 2/3 of the 40 members of a committee must vote in favor of a resolution for it to pass. What is the greatest number of members who could vote against the resolution and still have it pass? (A) 19 (8) 17 (C) 16 (D) 14 (E) 13 A club collected exactly $599 from its members. If each member contributed at least $12, what is the greatest number of members the club could have? (A) 43 (B) 44 (C) 49 (D) 50 (E) 51 599/12=49.912 Since n represents individual people, it must be a whole number; the greatest possible value of n is thus 49, not 50EMPOWERgmatRichC wrote: Hi studentsensual,
If a question expects you to 'round up' or 'round down', then you have to make sure to choose the answer that focuses on the specifics of the given prompt and answers the question that is asked:
Here, the specific information stated that AT LEAST 2/3 (meaning at least 66 2/3%) of the members must vote in favor of a resolution for it to pass. Since 26/40 is only 65%, then 26 people would NOT be enough. Thus, you have to round that number UP to 27 (because that's what the question requires). There could conceivably be questions that would require you to round down, but that's not what THIS question required.
GMAT assassins aren't born, they're made, Rich



EMPOWERgmat Instructor
Status: GMAT Assassin/CoFounder
Affiliations: EMPOWERgmat
Joined: 19 Dec 2014
Posts: 9290
Location: United States (CA)
GRE 1: 340 Q170 V170

Re: At least 2/3 of the 40 members of a committee must vote in [#permalink]
Show Tags
04 Feb 2016, 12:11
Hi studentsensual, These two questions provide you with different types of information/situations, so they require that you round in different 'directions.' In the second prompt, we're told that each member contributed AT LEAST $12, but that the total collected was $599. In this situation, the total number of members CANNOT be 50, since 50($12) = $600  and that total is just a little TOO HIGH. As such, we have to round DOWN. GMAT assassins aren't born, they're made, Rich
_________________
760+: Learn What GMAT Assassins Do to Score at the Highest Levels Contact Rich at: Rich.C@empowergmat.com
Rich Cohen
CoFounder & GMAT Assassin
***********************Select EMPOWERgmat Courses now include ALL 6 Official GMAC CATs!***********************



Manager
Joined: 11 Jul 2016
Posts: 86

At least 2/3rd ofthe 40 members of a committee.. [#permalink]
Show Tags
04 Sep 2016, 08:53
At least 2/3rd ofthe 40 members of a committee must vote in favor of a resolution for it to pass. What is the greatest number of members who could vote against the resolution and still have it pass?
(A) 19 (B) 17 (C) 16 (D) 14 (E) 13



BSchool Forum Moderator
Status: Aiming 800 Q51 V51
Joined: 18 Jul 2015
Posts: 1894
Location: India
Concentration: General Management, International Business
GMAT 1: 670 Q50 V32 GMAT 2: 700 Q50 V34
GPA: 3.65
WE: Brand Management (Health Care)

Re: At least 2/3rd ofthe 40 members of a committee.. [#permalink]
Show Tags
04 Sep 2016, 10:18
Manonamission wrote: At least 2/3rd ofthe 40 members of a committee must vote in favor of a resolution for it to pass. What is the greatest number of members who could vote against the resolution and still have it pass?
(A) 19 (B) 17 (C) 16 (D) 14 (E) 13 Atleast 2/3 votes in favor mean 2/3 of 40 ~27. Hence, Max against would be 4027 = 13. hence E
_________________
Good Luck



Math Forum Moderator
Status: QA & VA Forum Moderator
Joined: 11 Jun 2011
Posts: 2908
Location: India
GPA: 3.5
WE: Business Development (Commercial Banking)

Re: At least 2/3rd ofthe 40 members of a committee.. [#permalink]
Show Tags
04 Sep 2016, 13:09
Manonamission wrote: At least 2/3rd of the 40 members of a committee must vote in favor of a resolution for it to pass. What is the greatest number of members who could vote against the resolution and still have it pass? (A) 19 (B) 17 (C) 16 (D) 14 (E) 13 Vote in favour  \(\frac{2}{3} * 40\) = \(26 \frac{2}{3}\) ~ 27 No of voters who can vote against the resolution and still get it passed is (40  27) 13 Hence answer will be (E)
_________________
Thanks and Regards
Abhishek....
PLEASE FOLLOW THE RULES FOR POSTING IN QA AND VA FORUM AND USE SEARCH FUNCTION BEFORE POSTING NEW QUESTIONS
How to use Search Function in GMAT Club  Rules for Posting in QA forum  Writing Mathematical Formulas Rules for Posting in VA forum  Request Expert's Reply ( VA Forum Only )



EMPOWERgmat Instructor
Status: GMAT Assassin/CoFounder
Affiliations: EMPOWERgmat
Joined: 19 Dec 2014
Posts: 9290
Location: United States (CA)
GRE 1: 340 Q170 V170

Re: At least 2/3rd ofthe 40 members of a committee.. [#permalink]
Show Tags
04 Sep 2016, 20:59
Hi Manonamission, One of they 'keys' to this question is that you can't have a 'fraction of a person.' Thus, you have to pay attention to the question that is ASKED and think in terms of 'whole persons.' Here, we're told that AT LEAST 2/3 of the 40 members of a committee must vote in favor of a resolution for it to pass. Since 2/3 of 40 is 26.666666, but we can't have 26.666666 people, we have to round UP to 27. In contrast, 26 people would NOT be enough, since 26/40 = 13/20 = 65% (and not the 66 2/3% minimum that a resolution needs to be passed). Knowing that it would take AT LEAST 27 people to pass a resolution, the GREATEST number who could vote AGAINST the resolution in this case would be 4027 = 13. Final Answer: GMAT assassins aren't born, they're made, Rich
_________________
760+: Learn What GMAT Assassins Do to Score at the Highest Levels Contact Rich at: Rich.C@empowergmat.com
Rich Cohen
CoFounder & GMAT Assassin
***********************Select EMPOWERgmat Courses now include ALL 6 Official GMAC CATs!***********************



Math Expert
Joined: 02 Sep 2009
Posts: 39751

Re: At least 2/3 of the 40 members of a committee must vote in [#permalink]
Show Tags
04 Sep 2016, 22:33




Re: At least 2/3 of the 40 members of a committee must vote in
[#permalink]
04 Sep 2016, 22:33







