Check GMAT Club Decision Tracker for the Latest School Decision Releases https://gmatclub.com/AppTrack

 It is currently 30 May 2017, 03:39

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# At least 2/3 of the 40 members of a committee must vote in

Author Message
TAGS:

### Hide Tags

Manager
Joined: 02 Dec 2012
Posts: 178
Followers: 6

Kudos [?]: 2703 [3] , given: 0

At least 2/3 of the 40 members of a committee must vote in [#permalink]

### Show Tags

05 Dec 2012, 08:05
3
KUDOS
6
This post was
BOOKMARKED
00:00

Difficulty:

5% (low)

Question Stats:

74% (01:51) correct 26% (00:59) wrong based on 1041 sessions

### HideShow timer Statistics

At least 2/3 of the 40 members of a committee must vote in favor of a resolution for it to pass. What is the greatest number of members who could vote against the resolution and still have it pass?

(A) 19
(8) 17
(C) 16
(D) 14
(E) 13
[Reveal] Spoiler: OA
Math Expert
Joined: 02 Sep 2009
Posts: 39071
Followers: 7760

Kudos [?]: 106611 [3] , given: 11630

Re: At least 2/3 of the 40 members of a committee must vote in [#permalink]

### Show Tags

05 Dec 2012, 08:10
3
KUDOS
Expert's post
1
This post was
BOOKMARKED
At least 2/3 of the 40 members of a committee must vote in favor of a resolution for it to pass. What is the greatest number of members who could vote against the resolution and still have it pass?

(A) 19
(8) 17
(C) 16
(D) 14
(E) 13

Since, at least 2/3 of the 40 members of a committee must vote in favor, then at least $$\frac{2}{3}*40=26\frac{2}{3}$$ or at least 27 members should vote in favor. Therefore at most 13 members could vote against.

_________________
Manager
Joined: 01 Oct 2010
Posts: 82
Location: United States (NC)
GPA: 2.3
WE: Information Technology (Computer Software)
Followers: 1

Kudos [?]: 23 [0], given: 115

Re: At least 2/3 of the 40 members of a committee must vote in [#permalink]

### Show Tags

28 Sep 2013, 23:32
Bunuel wrote:
At least 2/3 of the 40 members of a committee must vote in favor of a resolution for it to pass. What is the greatest number of members who could vote against the resolution and still have it pass?

(A) 19
(8) 17
(C) 16
(D) 14
(E) 13

Since, at least 2/3 of the 40 members of a committee must vote in favor, then at least $$\frac{2}{3}*40=26\frac{2}{3}$$ or at least 27 members should vote in favor. Therefore at most 13 members could vote against.

What is wrong in the way I am doing this question?

It is given that at least 2/3rd of the 40 members should vote for the resolution. Since the members have to be a positive integer, I have considered 40 as 39 and then divided it by 3. After calculation, 26 members should vote for resolution. The remaining are 14 members who can vote against it; I marked D, which is incorrect.
_________________

---------------------------------------------------------------
Consider to give me kudos if my post helped you.

Director
Joined: 25 Apr 2012
Posts: 727
Location: India
GPA: 3.21
Followers: 44

Kudos [?]: 750 [1] , given: 723

Re: At least 2/3 of the 40 members of a committee must vote in [#permalink]

### Show Tags

29 Sep 2013, 00:12
1
KUDOS
AasaanHai wrote:
Bunuel wrote:
At least 2/3 of the 40 members of a committee must vote in favor of a resolution for it to pass. What is the greatest number of members who could vote against the resolution and still have it pass?

(A) 19
(8) 17
(C) 16
(D) 14
(E) 13

Since, at least 2/3 of the 40 members of a committee must vote in favor, then at least $$\frac{2}{3}*40=26\frac{2}{3}$$ or at least 27 members should vote in favor. Therefore at most 13 members could vote against.

What is wrong in the way I am doing this question?

It is given that at least 2/3rd of the 40 members should vote for the resolution. Since the members have to be a positive integer, I have considered 40 as 39 and then divided it by 3. After calculation, 26 members should vote for resolution. The remaining are 14 members who can vote against it; I marked D, which is incorrect.

Well you calculated for 39 members...How about the 1 that you left out....Since the Questions says At least 2/3 of 40 which is 26.666....Now atleast means it can be more and the least possible Integer value is 27....So most 13 members can vote against.
_________________

“If you can't fly then run, if you can't run then walk, if you can't walk then crawl, but whatever you do you have to keep moving forward.”

Manager
Joined: 12 Jan 2013
Posts: 220
Followers: 5

Kudos [?]: 72 [0], given: 47

Re: At least 2/3 of the 40 members of a committee must vote in [#permalink]

### Show Tags

19 Dec 2013, 02:38
At least 2/3 of the 40 members of a committee must vote in favor of a resolution for it to pass. What is the greatest number of members who could vote against the resolution and still have it pass?

(A) 19
(8) 17
(C) 16
(D) 14
(E) 13

40/3 = 13.3 (approx).. --> 13.3 x 2 = 26.6, so at least 27 people have to vote in favor for it to pass. ----> 13 at most can vote against for it to pass.
Manager
Joined: 12 Jan 2013
Posts: 220
Followers: 5

Kudos [?]: 72 [0], given: 47

Re: At least 2/3 of the 40 members of a committee must vote in [#permalink]

### Show Tags

10 Jan 2014, 01:39
At least 2/3 of the 40 members of a committee must vote in favor of a resolution for it to pass. What is the greatest number of members who could vote against the resolution and still have it pass?

(A) 19
(8) 17
(C) 16
(D) 14
(E) 13

Dividing 40/3 gives us 13.33333, thus 2/3 = 26.6666.. So in order for it to pass, at least 26.6 people need to vote on it, but of course we need an integer so at least 27 people need to vote on it (so, in practice, a bigger portion than 2/3).. That leaves us with 13 people that can vote against and still have it pass.

The non-integer throws us off and in some cases makes us round down. I think that's what they primarily want to test us on in this case, if we understand that we should round UP for required votes instead of round down.
Intern
Joined: 19 Jan 2014
Posts: 31
Followers: 0

Kudos [?]: 19 [0], given: 51

Re: At least 2/3 of the 40 members of a committee must vote in [#permalink]

### Show Tags

21 Feb 2014, 16:21
The way I calculated was. At least 2/3 so it's the minimum than the greatest portion we would have left would be 1/3. Hence (40x1)/3 13,3... = 13 people
GMAT Club Legend
Joined: 09 Sep 2013
Posts: 15528
Followers: 651

Kudos [?]: 211 [0], given: 0

Re: At least 2/3 of the 40 members of a committee must vote in [#permalink]

### Show Tags

10 Mar 2015, 19:55
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
Intern
Joined: 27 Oct 2015
Posts: 18
Followers: 2

Kudos [?]: 4 [0], given: 175

Re: At least 2/3 of the 40 members of a committee must vote in [#permalink]

### Show Tags

26 Jan 2016, 22:59
2/3 of 40 which is 26.666, there is no 0.666 person, so I decided 2/3 of 40 is 26, thus 40-26=14, at least means minimum, not maximum, so minimum possible numbers, then it's logical to consider 26, moreover question asks the greatest number of members, how could I realize wherther to round up or not?

Thanks!

WoundedTiger wrote:
AasaanHai wrote:
Bunuel wrote:
Since, at least 2/3 of the 40 members of a committee must vote in favor, then at least $$\frac{2}{3}*40=26\frac{2}{3}$$ or at least 27 members should vote in favor. Therefore at most 13 members could vote against.

What is wrong in the way I am doing this question?

It is given that at least 2/3rd of the 40 members should vote for the resolution. Since the members have to be a positive integer, I have considered 40 as 39 and then divided it by 3. After calculation, 26 members should vote for resolution. The remaining are 14 members who can vote against it; I marked D, which is incorrect.

Well you calculated for 39 members...How about the 1 that you left out....Since the Questions says At least 2/3 of 40 which is 26.666....Now atleast means it can be more and the least possible Integer value is 27....So most 13 members can vote against.
EMPOWERgmat Instructor
Status: GMAT Assassin/Co-Founder
Affiliations: EMPOWERgmat
Joined: 19 Dec 2014
Posts: 9135
Location: United States (CA)
GMAT 1: 800 Q51 V49
GRE 1: 340 Q170 V170
Followers: 448

Kudos [?]: 2885 [1] , given: 169

Re: At least 2/3 of the 40 members of a committee must vote in [#permalink]

### Show Tags

30 Jan 2016, 10:59
1
KUDOS
Expert's post
Hi studentsensual,

You seem to understand that you can't have a 'fraction of a person' in these types of questions. Thus, you have to pay attention to the question that is ASKED and think in terms of 'whole persons.'

Here, we're told that AT LEAST 2/3 of the 40 members of a committee must vote in favor of a resolution for it to pass. Since 2/3 of 40 is 26.666666, but we can't have 26.666666 people, we have to round UP to 27. In contrast, 26 people would NOT be enough, since 26/40 = 13/20 = 65% (and not the 66 2/3% minimum that a resolution needs to be passed).

Knowing that it would take AT LEAST 27 people to pass a resolution, the GREATEST number who could vote AGAINST the resolution in this case would be 40-27 = 13.

[Reveal] Spoiler:
E

GMAT assassins aren't born, they're made,
Rich
_________________

760+: Learn What GMAT Assassins Do to Score at the Highest Levels
Contact Rich at: Rich.C@empowergmat.com

# Rich Cohen

Co-Founder & GMAT Assassin

# Special Offer: Save $75 + GMAT Club Tests 60-point improvement guarantee www.empowergmat.com/ ***********************Select EMPOWERgmat Courses now include ALL 6 Official GMAC CATs!*********************** Intern Joined: 27 Oct 2015 Posts: 18 Followers: 2 Kudos [?]: 4 [0], given: 175 Re: At least 2/3 of the 40 members of a committee must vote in [#permalink] ### Show Tags 31 Jan 2016, 19:31 So, when dealing with individuals, should I every time to round the numbers up? Thanks! EMPOWERgmatRichC wrote: Hi studentsensual, You seem to understand that you can't have a 'fraction of a person' in these types of questions. Thus, you have to pay attention to the question that is ASKED and think in terms of 'whole persons.' Here, we're told that AT LEAST 2/3 of the 40 members of a committee must vote in favor of a resolution for it to pass. Since 2/3 of 40 is 26.666666, but we can't have 26.666666 people, we have to round UP to 27. In contrast, 26 people would NOT be enough, since 26/40 = 13/20 = 65% (and not the 66 2/3% minimum that a resolution needs to be passed). Knowing that it would take AT LEAST 27 people to pass a resolution, the GREATEST number who could vote AGAINST the resolution in this case would be 40-27 = 13. Final Answer: [Reveal] Spoiler: E GMAT assassins aren't born, they're made, Rich EMPOWERgmat Instructor Status: GMAT Assassin/Co-Founder Affiliations: EMPOWERgmat Joined: 19 Dec 2014 Posts: 9135 Location: United States (CA) GMAT 1: 800 Q51 V49 GRE 1: 340 Q170 V170 Followers: 448 Kudos [?]: 2885 [0], given: 169 Re: At least 2/3 of the 40 members of a committee must vote in [#permalink] ### Show Tags 31 Jan 2016, 23:50 Hi studentsensual, If a question expects you to 'round up' or 'round down', then you have to make sure to choose the answer that focuses on the specifics of the given prompt and answers the question that is asked: Here, the specific information stated that AT LEAST 2/3 (meaning at least 66 2/3%) of the members must vote in favor of a resolution for it to pass. Since 26/40 is only 65%, then 26 people would NOT be enough. Thus, you have to round that number UP to 27 (because that's what the question requires). There could conceivably be questions that would require you to round down, but that's not what THIS question required. GMAT assassins aren't born, they're made, Rich _________________ 760+: Learn What GMAT Assassins Do to Score at the Highest Levels Contact Rich at: Rich.C@empowergmat.com # Rich Cohen Co-Founder & GMAT Assassin # Special Offer: Save$75 + GMAT Club Tests

60-point improvement guarantee
www.empowergmat.com/

***********************Select EMPOWERgmat Courses now include ALL 6 Official GMAC CATs!***********************

Intern
Joined: 27 Oct 2015
Posts: 18
Followers: 2

Kudos [?]: 4 [0], given: 175

Re: At least 2/3 of the 40 members of a committee must vote in [#permalink]

### Show Tags

04 Feb 2016, 06:00

At least 2/3 of the 40 members of a committee must vote in favor of a resolution for it to pass. What is the greatest number of members who could vote against the resolution and still have it pass?
(A) 19
(8) 17
(C) 16
(D) 14
(E) 13

A club collected exactly $599 from its members. If each member contributed at least$12, what is the greatest number of members the club could have?
(A) 43
(B) 44
(C) 49
(D) 50
(E) 51

599/12=49.912
Since n represents individual people, it must be a whole number; the greatest possible value of n is thus 49, not 50

EMPOWERgmatRichC wrote:
Hi studentsensual,

If a question expects you to 'round up' or 'round down', then you have to make sure to choose the answer that focuses on the specifics of the given prompt and answers the question that is asked:

Here, the specific information stated that AT LEAST 2/3 (meaning at least 66 2/3%) of the members must vote in favor of a resolution for it to pass. Since 26/40 is only 65%, then 26 people would NOT be enough. Thus, you have to round that number UP to 27 (because that's what the question requires). There could conceivably be questions that would require you to round down, but that's not what THIS question required.

GMAT assassins aren't born, they're made,
Rich
EMPOWERgmat Instructor
Status: GMAT Assassin/Co-Founder
Affiliations: EMPOWERgmat
Joined: 19 Dec 2014
Posts: 9135
Location: United States (CA)
GMAT 1: 800 Q51 V49
GRE 1: 340 Q170 V170
Followers: 448

Kudos [?]: 2885 [0], given: 169

Re: At least 2/3 of the 40 members of a committee must vote in [#permalink]

### Show Tags

04 Feb 2016, 12:11
Hi studentsensual,

These two questions provide you with different types of information/situations, so they require that you round in different 'directions.' In the second prompt, we're told that each member contributed AT LEAST $12, but that the total collected was$599. In this situation, the total number of members CANNOT be 50, since 50($12) =$600 - and that total is just a little TOO HIGH. As such, we have to round DOWN.

GMAT assassins aren't born, they're made,
Rich
_________________

760+: Learn What GMAT Assassins Do to Score at the Highest Levels
Contact Rich at: Rich.C@empowergmat.com

# Rich Cohen

Co-Founder & GMAT Assassin

# Special Offer: Save $75 + GMAT Club Tests 60-point improvement guarantee www.empowergmat.com/ ***********************Select EMPOWERgmat Courses now include ALL 6 Official GMAC CATs!*********************** Manager Joined: 11 Jul 2016 Posts: 86 Followers: 0 Kudos [?]: 20 [0], given: 87 At least 2/3rd ofthe 40 members of a committee.. [#permalink] ### Show Tags 04 Sep 2016, 08:53 At least 2/3rd ofthe 40 members of a committee must vote in favor of a resolution for it to pass. What is the greatest number of members who could vote against the resolution and still have it pass? (A) 19 (B) 17 (C) 16 (D) 14 (E) 13 BSchool Forum Moderator Status: Aiming 800 Q51 V51 Joined: 18 Jul 2015 Posts: 1723 Location: India Concentration: General Management, International Business GMAT 1: 670 Q50 V32 GMAT 2: 700 Q50 V34 GPA: 3.65 WE: Brand Management (Health Care) Followers: 39 Kudos [?]: 407 [0], given: 52 Re: At least 2/3rd ofthe 40 members of a committee.. [#permalink] ### Show Tags 04 Sep 2016, 10:18 Manonamission wrote: At least 2/3rd ofthe 40 members of a committee must vote in favor of a resolution for it to pass. What is the greatest number of members who could vote against the resolution and still have it pass? (A) 19 (B) 17 (C) 16 (D) 14 (E) 13 Atleast 2/3 votes in favor mean 2/3 of 40 ~27. Hence, Max against would be 40-27 = 13. hence E _________________ Good Luck Math Forum Moderator Status: QA & VA Forum Moderator Joined: 11 Jun 2011 Posts: 2698 Location: India GPA: 3.5 WE: Business Development (Commercial Banking) Followers: 111 Kudos [?]: 866 [0], given: 324 Re: At least 2/3rd ofthe 40 members of a committee.. [#permalink] ### Show Tags 04 Sep 2016, 13:09 Manonamission wrote: At least 2/3rd of the 40 members of a committee must vote in favor of a resolution for it to pass. What is the greatest number of members who could vote against the resolution and still have it pass? (A) 19 (B) 17 (C) 16 (D) 14 (E) 13 Vote in favour - $$\frac{2}{3} * 40$$ = $$26 \frac{2}{3}$$ ~ 27 No of voters who can vote against the resolution and still get it passed is (40 - 27) 13 Hence answer will be (E) _________________ Thanks and Regards Abhishek.... PLEASE FOLLOW THE RULES FOR POSTING IN QA AND VA FORUM AND USE SEARCH FUNCTION BEFORE POSTING NEW QUESTIONS How to use Search Function in GMAT Club | Rules for Posting in QA forum | Writing Mathematical Formulas |Rules for Posting in VA forum | Request Expert's Reply ( VA Forum Only ) EMPOWERgmat Instructor Status: GMAT Assassin/Co-Founder Affiliations: EMPOWERgmat Joined: 19 Dec 2014 Posts: 9135 Location: United States (CA) GMAT 1: 800 Q51 V49 GRE 1: 340 Q170 V170 Followers: 448 Kudos [?]: 2885 [0], given: 169 Re: At least 2/3rd ofthe 40 members of a committee.. [#permalink] ### Show Tags 04 Sep 2016, 20:59 Hi Manonamission, One of they 'keys' to this question is that you can't have a 'fraction of a person.' Thus, you have to pay attention to the question that is ASKED and think in terms of 'whole persons.' Here, we're told that AT LEAST 2/3 of the 40 members of a committee must vote in favor of a resolution for it to pass. Since 2/3 of 40 is 26.666666, but we can't have 26.666666 people, we have to round UP to 27. In contrast, 26 people would NOT be enough, since 26/40 = 13/20 = 65% (and not the 66 2/3% minimum that a resolution needs to be passed). Knowing that it would take AT LEAST 27 people to pass a resolution, the GREATEST number who could vote AGAINST the resolution in this case would be 40-27 = 13. Final Answer: [Reveal] Spoiler: E GMAT assassins aren't born, they're made, Rich _________________ 760+: Learn What GMAT Assassins Do to Score at the Highest Levels Contact Rich at: Rich.C@empowergmat.com # Rich Cohen Co-Founder & GMAT Assassin # Special Offer: Save$75 + GMAT Club Tests

60-point improvement guarantee
www.empowergmat.com/

***********************Select EMPOWERgmat Courses now include ALL 6 Official GMAC CATs!***********************

Math Expert
Joined: 02 Sep 2009
Posts: 39071
Followers: 7760

Kudos [?]: 106611 [0], given: 11630

Re: At least 2/3 of the 40 members of a committee must vote in [#permalink]

### Show Tags

04 Sep 2016, 22:33
Manonamission wrote:
At least 2/3rd ofthe 40 members of a committee must vote in favor of a resolution for it to pass.
What is the greatest number of members who could vote against the resolution and still have it pass?

(A) 19
(B) 17
(C) 16
(D) 14
(E) 13

Merging topics. Please search before posting.
_________________
Re: At least 2/3 of the 40 members of a committee must vote in   [#permalink] 04 Sep 2016, 22:33
Similar topics Replies Last post
Similar
Topics:
3 Members of a student parliament took a vote on a proposition for a new 3 27 Feb 2017, 11:58
3 A student committee that must consists of 5 members is to be formed 7 22 May 2017, 18:53
19 A university needs to select a nine-member committee on extr 10 12 Sep 2016, 11:50
42 A committee that includes 6 members is about to be divided 24 16 Apr 2017, 15:10
11 A five-member committee is to be formed from a group of five 20 28 Sep 2016, 09:49
Display posts from previous: Sort by