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At some point while traveling to a city Mr. Hock increased his speed b

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At some point while traveling to a city Mr. Hock increased his speed b  [#permalink]

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New post 09 Feb 2019, 10:22
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  25% (medium)

Question Stats:

76% (01:54) correct 24% (02:51) wrong based on 83 sessions

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At some point while traveling to a city Mr. Hock increased his speed by 20%. After traveling for some distance at that speed, he reduced his speed by 15%. After this deduction Mr. Hock's speed was 51 km/hour. What was Mr. Hock's original speed?

A. 42 km/hour
B. 47 km/hour
C. 49 km/hour
D. 50 km/hour
E. 52 km/hour
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Re: At some point while traveling to a city Mr. Hock increased his speed b  [#permalink]

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New post 09 Feb 2019, 10:36
akurathi12 wrote:
At some point while traveling to a city Mr. Hock increased his speed by 20%. After traveling for some distance at that speed, he reduced his speed by 15%. After this deduction Mr. Hock's speed was 51 km/hour. What was Mr. Hock's original speed?

A. 42 km/hour
B. 47 km/hour
C. 49 km/hour
D. 50 km/hour
E. 52 km/hour


Successive % change = 20 - 15 -300/100 = 2%

Now original speed = 51 - 2% 51 = 51-1

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Re: At some point while traveling to a city Mr. Hock increased his speed b  [#permalink]

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New post 11 Feb 2019, 17:42
Increase 20% = 1+.2 =1.2
Decrease 15% = 1-.15= .85

Multiply (1.2)*(.85)= (12)*(80+5)= 960+60=1020 move the decimal =1.020% increase
If the final speed was 51 its original speed must be around 50 km/hr

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At some point while traveling to a city Mr. Hock increased his speed b  [#permalink]

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New post 27 Feb 2019, 23:28
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akurathi12 wrote:
At some point while traveling to a city Mr. Hock increased his speed by 20%. After traveling for some distance at that speed, he reduced his speed by 15%. After this deduction Mr. Hock's speed was 51 km/hour. What was Mr. Hock's original speed?

A. 42 km/hour
B. 47 km/hour
C. 49 km/hour
D. 50 km/hour
E. 52 km/hour


Let the original speed = X km/hr

Speed increased by 20% = X + 0.20X = 1.2X

Now the speed is decreased by 15% = 1.2X - 1.2 * 0.15 = 1.02X

Now as per question we know,

1.02X = 51

X = 51 * 100 / (102)

X = 50 km/hr (D)

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At some point while traveling to a city Mr. Hock increased his speed b   [#permalink] 27 Feb 2019, 23:28
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At some point while traveling to a city Mr. Hock increased his speed b

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