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At Springfield High, three-fourths of the male students and

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Senior Manager
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Status: D-Day is on February 10th. and I am not stressed
Affiliations: American Management association, American Association of financial accountants
Joined: 12 Apr 2011
Posts: 252

Kudos [?]: 370 [0], given: 52

Location: Kuwait
Schools: Columbia university
At Springfield High, three-fourths of the male students and [#permalink]

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New post 16 Jan 2012, 10:50
00:00
A
B
C
D
E

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(N/A)

Question Stats:

75% (01:49) correct 25% (00:00) wrong based on 8 sessions

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At Springfield High, three-fourths of the male students and one-half of the female students speak a foreign language. If the number of males is two-thirds the number of females, what fraction of the students speak a foreign language?

A. 1/3
B. 2/3
C. 1/2
D. 4/3
E. 3/5
[Reveal] Spoiler: OA

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Kudos [?]: 370 [0], given: 52

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Senior Manager
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Joined: 30 Aug 2009
Posts: 283

Kudos [?]: 191 [1], given: 5

Location: India
Concentration: General Management
Re: At Springfield High, three-fourths of the male students and [#permalink]

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New post 16 Jan 2012, 12:27
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manalq8 wrote:
At Springfield High, three-fourths of the male students and one-half of the female students speak a foreign language. If the number of males is two-thirds the number of females, what fraction of the students speak a foreign language?

a)1/3

b)2/3

c)1/2

d)4/3

e)3/5

I attempted this question but every time I get B. the OA is E

my approach was choosing a number, in this case I chose 120 as the total students, and solved it from there.

can anyone please help
thanks


Consider total students = 120

given, M = (2/3)F

so F= 72 and M = 48

3/4M +1/2F speak foreign language = (3/4)* 48 + (1/2)*72 = 36+36 = 72

ratio = 72/120 = 3/5

E

Kudos [?]: 191 [1], given: 5

Senior Manager
Senior Manager
avatar
Status: D-Day is on February 10th. and I am not stressed
Affiliations: American Management association, American Association of financial accountants
Joined: 12 Apr 2011
Posts: 252

Kudos [?]: 370 [0], given: 52

Location: Kuwait
Schools: Columbia university
Re: At Springfield High, three-fourths of the male students and [#permalink]

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New post 16 Jan 2012, 14:42
oh I see. thanks alot. i was doing it 2/3 of 120.
thanks
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Kudos [?]: 370 [0], given: 52

Manager
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Status: MBA Aspirant
Joined: 12 Jun 2010
Posts: 171

Kudos [?]: 102 [0], given: 1

Location: India
Concentration: Finance, International Business
WE: Information Technology (Investment Banking)
Re: At Springfield High, three-fourths of the male students and [#permalink]

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New post 16 Jan 2012, 20:34
Ans is E
let m be the no of male students
f be the no of female students and x be the total no of students
so m+f = x and given foreign language = 3/4m+1/2f
and m=2/3f on solving this we get the ans as E

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Re: At Springfield High, three-fourths of the male students and [#permalink]

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New post 23 Feb 2012, 10:52
may i ask why 120? why not 100

so the formula would be f+(2/3)f=100

f=60 a nice round number.
so m= 40

therefore 30 males and 30 females know a foreign language. that is 60/100 or 3/5

I personally find 100 an easier number and was wondering why you picked 120. But as long as it works it works

Kudos [?]: 5 [0], given: 5

Re: At Springfield High, three-fourths of the male students and   [#permalink] 23 Feb 2012, 10:52
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At Springfield High, three-fourths of the male students and

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