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# At the start of his 3 years graduation program Mr. John bought a car a

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Manager
Joined: 25 Dec 2018
Posts: 91
Location: India
GMAT 1: 490 Q47 V13
GPA: 2.86
At the start of his 3 years graduation program Mr. John bought a car a  [#permalink]

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07 Jan 2019, 09:47
2
3
00:00

Difficulty:

75% (hard)

Question Stats:

52% (02:25) correct 48% (01:40) wrong based on 42 sessions

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At the start of his 3 years graduation program Mr. John bought a car at the market price of $x and sold it to Mr.Max at the end of 3rd year at the market price of$y.If the market price of car depreciated by 20%, 50/3% and 25% respectively in 3 consecutive years, which of the following is true?

A. 3x-2y=0
B. 2x=y
C. x+y=3y
D. 4x-3y=3x
E. None of these
Manager
Joined: 09 Mar 2018
Posts: 246
Location: India
At the start of his 3 years graduation program Mr. John bought a car a  [#permalink]

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07 Jan 2019, 10:03
2
akurathi12 wrote:
At the start of his 3 years graduation program Mr. John bought a car at the market price of $x and sold it to Mr.Max at the end of 3rd year at the market price of$y.If the market price of car depreciated by 20%, 50/3% and 25% respectively in 3 consecutive years, which of the following is true?

A. 3x-2y=0
B. 2x=y
C. x+y=3y
D. 4x-3y=3x
E. None of these

After brain storming over this question for 3 mins, I decided to Take initial cost as 100, x = 100
A. 3x-2y=0 => 3x=2y
B. 2x=y => This case is not possible, since the value is depreciating, how can the final value be greater than initial value- Eliminated this
C. x+y=3y => x = 2y
D. 4x-3y=3x => x= 3y

x = 100, Depreciation = D
D1 for 20% , Value of x after D1 = 80
D2 for 50/3 %, Value of x after D2 = 67
D3 for 25%, Value of x after D3 = 51,which is the value for y

x= 2y
This is in line with Option C

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Manager
Status: Manager
Joined: 27 Oct 2018
Posts: 108
Location: Malaysia
GPA: 3.67
WE: Pharmaceuticals (Health Care)
At the start of his 3 years graduation program Mr. John bought a car a  [#permalink]

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07 Jan 2019, 10:14
2
the awkward part is to translate this : 50/3 % = $$(\frac{50}{3})/100 = \frac{50}{300}$$

$$x * (\frac{100}{100}-\frac{20}{100})(\frac{300}{300}-\frac{50}{300})(\frac{100}{100}-\frac{25}{100}) = y$$

$$x * \frac{4}{5}*\frac{5}{6}*\frac{3}{4} = y$$

$$x * \frac{1}{2} = y$$

$$x = 2y$$

$$x + y = 3y$$

so C
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Manager
Joined: 28 Jul 2016
Posts: 212
Location: India
Concentration: Finance, Human Resources
GPA: 3.97
Re: At the start of his 3 years graduation program Mr. John bought a car a  [#permalink]

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20 Jan 2019, 11:20
Question was pretty simple.
The answer choices were quite messed up
The equation simplifies to:
$$(4*5*3)/(5*6*4)*x=y$$
$$1/2x= y$$
therefor x= 2y
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Re: At the start of his 3 years graduation program Mr. John bought a car a &nbs [#permalink] 20 Jan 2019, 11:20
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