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# Attached are 2 questions i am not sure how to get to the

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Attached are 2 questions i am not sure how to get to the [#permalink]

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03 Feb 2007, 10:59
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Attached are 2 questions i am not sure how to get to the right answer. Can anyone help?

Thanks!!!!!!
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gmatprep3_quantmissed_feb2.xls [94.5 KiB]

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03 Feb 2007, 11:39
For the first one:

5^21 * 4^11 = 2 * 10^n

5^21 * (2^2)11 = 2 * 10^n

5^21 * 2^22 = 2 * 10^n

5^21 * 2^21 * 2 = 2* 10^n

2 * 10^21 = 2 * 10^n

Hence n=21

For the second one:

You can select 2 men out of 4 in 4C2 ways = 6

You can select 2 women out of 3 in 3C2 ways = 3

And the number of task force formed by 2 men and 2 women = 6*3 = 18
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03 Feb 2007, 11:40
Solution to first one
5^21 * 4^11 =2 *10^n
5^21 * 4 *4^10/2=10^n
5*5^20 *2*2^20=10^n
10 *10^20=10^n
10^21=10^n
n =21

Solution to second one
4c2*3c2
03 Feb 2007, 11:40
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