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Ayayai electronics is a company manufacturing MP3 players. Ayayai manu

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New post 07 Oct 2016, 02:42
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A
B
C
D
E

Difficulty:

  55% (hard)

Question Stats:

72% (03:33) correct 28% (03:19) wrong based on 176 sessions

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Ayayai electronics is a company manufacturing MP3 players. Ayayai manufactures only two players: iMe and iMine. Either player is assembled using a LCD screen or an OLED screen. Excluding the expensive OLED-iMine model, Ayayai manufactures 21,000 players per month. Every month, Ayayai manufactures 11,000 players with an OLED screen, and 12,000 iMine models. If Ayayai manufactures 8000 LCD iMe models monthly, how many players (of all models) does Ayayai manufacture per month?

A. 24,000
B. 25,000
C. 26,000
D. 27,000
E. 28,000

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New post 07 Oct 2016, 03:34
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1
Let x be the iMine LCD players
Let y be the iMe OLED players

8000 + x + y = 21000
x + y = 13000
Assume 6000,7000 for x and y.

6000 + iMine OLED = 11000. iMine OLED = 5000.
Hence total number of players = 8000 + x + y + 5000 = 26000(Option C)
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Ayayai electronics is a company manufacturing MP3 players. Ayayai manu  [#permalink]

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New post 05 May 2017, 21:05
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Bunuel wrote:
Ayayai electronics is a company manufacturing MP3 players. Ayayai manufactures only two players: iMe and iMine. Either player is assembled using a LCD screen or an OLED screen. Excluding the expensive OLED-iMine model, Ayayai manufactures 21,000 players per month. Every month, Ayayai manufactures 11,000 players with an OLED screen, and 12,000 iMine models. If Ayayai manufactures 8000 LCD iMe models monthly, how many players (of all models) does Ayayai manufacture per month?

A. 24,000
B. 25,000
C. 26,000
D. 27,000
E. 28,000



Please follow attached fig below


given 8+x+y= 21
thus x+y=13--------(I)
Also 8+x+11=8+y+12=total(T)-----(III)
thus x-y=1-------(II)
equating (I) &(II)
x=7 & y= 6
substitute x or y in (III) to get total= 26
Ans C
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Re: Ayayai electronics is a company manufacturing MP3 players. Ayayai manu  [#permalink]

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New post 26 Jul 2017, 16:44
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Bunuel wrote:
Ayayai electronics is a company manufacturing MP3 players. Ayayai manufactures only two players: iMe and iMine. Either player is assembled using a LCD screen or an OLED screen. Excluding the expensive OLED-iMine model, Ayayai manufactures 21,000 players per month. Every month, Ayayai manufactures 11,000 players with an OLED screen, and 12,000 iMine models. If Ayayai manufactures 8000 LCD iMe models monthly, how many players (of all models) does Ayayai manufacture per month?

A. 24,000
B. 25,000
C. 26,000
D. 27,000
E. 28,000


We can let x = the number of OLED-iMine model players, y = the number of OLED-iMe model players, z = the number of LCD-iMine model players, and w = the number of LCD-iMe model players. We need to find the value of x + y + z + w.

We are given the following:

y + z + w = 21,000

x + y = 11,000

x + z = 12,000

and

w = 8,000

Substituting w = 8,000 into the first equation, we have y + z + 8,000 = 21,000, or y + z = 13,000.

Adding the equations for y + z, x + y, and x + z, we get:

y + z + x + y + x + z = 2(x + y + z) = 13,000 + 11,000 + 12,000 = 36,000.

Thus, x + y + z = 18,000. Adding w = 8,000, we get x + y + z + w = 26,000.

Answer: C
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Re: Ayayai electronics is a company manufacturing MP3 players. Ayayai manu   [#permalink] 26 Jul 2017, 16:44
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