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Before you spend too much time on this one  be warned  I [#permalink]
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22 May 2007, 11:38
This topic is locked. If you want to discuss this question please repost it in the respective forum.
Before you spend too much time on this one  be warned  I don't think the correct answer is amoung the choices; I could be wrong.
Together Andrea and Brian weigh p pounds. Brian weighs 10 pounds more than andrea. Brian and Andrea's dog, Cubby, weighs p/4 more pounds than andrea. In terms of p what is Cubby's weight in pounds?
a (p/2) 10
b (3p/4) 5
c (3p/2)5
d (5p/4)10
e 5p5



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Re: PR BIN 4 Errata? [#permalink]
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22 May 2007, 11:54
gmatiscoming wrote: Before you spend too much time on this one  be warned  I don't think the correct answer is amoung the choices; I could be wrong.
Together Andrea and Brian weigh p pounds. Brian weighs 10 pounds more than andrea. Brian and Andrea's dog, Cubby, weighs p/4 more pounds than andrea. In terms of p what is Cubby's weight in pounds?
a (p/2) 10 b (3p/4) 5 c (3p/2)5 d (5p/4)10 e 5p5
A+B=P
B=A+10
B+C=A+P/4
2A+10=P A=(P10)/2
C=(P10)/2+P/4(P10)/210
C=P/410



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Re: PR BIN 4 Errata? [#permalink]
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22 May 2007, 12:17
gmatiscoming wrote: Before you spend too much time on this one  be warned  I don't think the correct answer is amoung the choices; I could be wrong.
Together Andrea and Brian weigh p pounds. Brian weighs 10 pounds more than andrea. Brian and Andrea's dog, Cubby, weighs p/4 more pounds than andrea. In terms of p what is Cubby's weight in pounds?
a (p/2) 10 b (3p/4) 5 c (3p/2)5 d (5p/4)10 e 5p5
A + B = P
B = A + 10
C= A + P/4
By substituting B in the second equation into the first equation, we get:
A + A + 10 = P ==> 2A + 10 = P ==> A = (P10)/2
Substitute this A into the third equation
C = (P10)/2 + P/4
Multiply the first value by 2 to get common denominators
C = (2P20)/4 + P/4
Multiply both sides by 4
4C = 2P20 + P
4C = 3P20
C = 3P/4  5
Answer : B



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Answer is B.
[1] A+B=p
[2] B=A+10
[3] C=(p/4)+A
Now, plug eq. [2] into eq. [1]:
A+A+10=p
2A+10=p
2A=p10
A=(p/2)5
Now plug this new eq. into eq. [3]:
C=(p/4)+(p/2)5
C=(p/4)+(2p/4)5
C=(3p/4)5
What's the OA?



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Joined: 04 May 2007
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they list the OA as B; but I took the line Brian and (+) Cubby weigh p/4 more than Andrea to mean:
B+C=A +p/4
which gives you an answer choice that isn't available. I guess I need to be more careful... ??



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Joined: 08 Jun 2005
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Gmatiscoming congratulations ! I believe that you found a mistake in PR !!!
your logic about B+C is correct ! PR wording is wrong.
I have the PR and the mistake clearly comes from Cubby weight. The official explanation states that Cubby weight is P/4 punds more then Andrea while the stem clearly states that Brain and Cubby togther whigh P/4 more then Andrea !!! .
should I EMail PR ?



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Joined: 04 Feb 2007
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Is PR's wording really wrong ?
It clearly says " Brian and Andrea's dog, C....., weighs (Singular & not plural).......tricky language , isn't it ?



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vidyasagar wrote: Is PR's wording really wrong ?
It clearly says " Brian and Andrea's dog, C....., weighs (Singular & not plural).......tricky language , isn't it ?
If that's singular , why does it mention Brian ? should say "Andrea's dog, C....., weighs".



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I never even thought to think of singular vs. plural on this question... i guess you really have to be careful on the GMAT; but the line says "Brian and Andrea's dog, Cubby, weighs p/4"
so this almost becomes a grammar question too. but, shouldn't it be
"Brian and Andrea's dog each weigh p/4 pounds more than Andrea"???



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i got: (p/4)  10.........
i think the answer isn't there.



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i got B....... took me 30 secs........
its easy guys........
A=PB
B=A+10
C=A+ P/4
we need C.........
so, find A in terms of p.......
substitute value of B in first eq......
=> A=(P10)/2
put the value of A in third eq......... and simplify.........
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devansh_god wrote: i got B....... took me 30 secs........ its easy guys........
A=PB B=A+10 C=A+ P/4
we need C......... so, find A in terms of p....... substitute value of B in first eq......
=> A=(P10)/2 put the value of A in third eq......... and simplify.........
quote "Brian and Andrea's dog, Cubby, weighs p/4 more pounds than andrea.."
C=A+ P/4 , does not compute !
should have been "Brian and Andrea's" dog, Cubby, weighs p/4 more pounds than andrea.."
Last edited by KillerSquirrel on 24 May 2007, 13:25, edited 1 time in total.



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Re: PR BIN 4 Errata? [#permalink]
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24 May 2007, 08:15
gmatiscoming wrote: Before you spend too much time on this one  be warned  I don't think the correct answer is amoung the choices; I could be wrong.
Together Andrea and Brian weigh p pounds. Brian weighs 10 pounds more than andrea. Brian and Andrea's dog, Cubby, weighs p/4 more pounds than andrea. In terms of p what is Cubby's weight in pounds?
a (p/2) 10 b (3p/4) 5 c (3p/2)5 d (5p/4)10 e 5p5
Answer is B.
Solve from the options.
put (3p/4)  5 = A + (p/4)
Solve for A and B and then see which equations satisfies A + B = P




Re: PR BIN 4 Errata?
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24 May 2007, 08:15






