y=\(\frac{1}{2}−\frac{1}{3}+\frac{1}{6}−\frac{1}{10}+\frac{1}{12}−\frac{1}{14}+\frac{1}{16}\)
Best approximation for y is
A. 0.1
B. 0.31
C. 0.35
D. 0.4
E. 0.6
y=\(\frac{1}{2}−\frac{1}{3}+\frac{1}{6}−\frac{1}{10}+\frac{1}{12}−\frac{1}{14}+\frac{1}{16}\)
= \(\frac{1}{6}+\frac{1}{6}−\frac{1}{10}+\frac{1}{12}−\frac{1}{14}+\frac{1}{16}\)
= \(\frac{1}{3}−\frac{1}{10}+\frac{1}{12}−\frac{1}{14}+\frac{1}{16}\)
= \(\frac{1}{3}−\frac{1}{60}−\frac{1}{112}\)
As \(\frac{1}{10}-\frac{1}{12}=\frac{1}{60}\) and \(\frac{1}{14}-\frac{1}{16}=\frac{1}{112}\)
Above both values make a difference in hundredth position only.
Hence among values less than 0.33 B is nearer.
Answer B.
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Ephemeral Epiphany..!
GMATPREP1 590(Q48,V23) March 6, 2019
GMATPREP2 610(Q44,V29) June 10, 2019
GMATPREPSoft1 680(Q48,V35) June 26, 2019