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Beth began a 16-day exercise program by doing 5 sit-ups on the first

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Beth began a 16-day exercise program by doing 5 sit-ups on the first  [#permalink]

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New post 29 Nov 2019, 19:19
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B
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Beth began a 16-day exercise program by doing 5 sit-ups on the first day. If she does 6 sit-ups on the second day, 7 sit-ups on the third day, and if each day thereafter she does 1 more sit-up than on the previous day, what is the total number of sit-ups that Beth will do during the 16-day program?

a) 126
b) 200
c) 210
d) 410
e) 420
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Re: Beth began a 16-day exercise program by doing 5 sit-ups on the first  [#permalink]

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New post 29 Nov 2019, 22:52
Given an a.p where a= 5
n = 16 and d= 1
We are asked sum of A.P
which is
S= \(\frac{n}{2}(2a+(n-1)d)\)
= \(\frac{16}{2}(10+15*1)\)
= 200
hence answer B
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Re: Beth began a 16-day exercise program by doing 5 sit-ups on the first  [#permalink]

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New post 30 Nov 2019, 07:04
It seems to present the sequence. First day = 5, second day =6, third day = 7,,,,,,16th = 20

Sum = first observation + last observation* total days(n)/2
= 5+20 * 16/2
=25*16/2
=25*8
=200
Hence, B.
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Re: Beth began a 16-day exercise program by doing 5 sit-ups on the first  [#permalink]

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New post 30 Nov 2019, 09:28
sharbeario wrote:
Beth began a 16-day exercise program by doing 5 sit-ups on the first day. If she does 6 sit-ups on the second day, 7 sit-ups on the third day, and if each day thereafter she does 1 more sit-up than on the previous day, what is the total number of sit-ups that Beth will do during the 16-day program?

a) 126
b) 200
c) 210
d) 410
e) 420


5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20= 25*8=200
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Re: Beth began a 16-day exercise program by doing 5 sit-ups on the first   [#permalink] 30 Nov 2019, 09:28
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