Neferteena wrote:
I dont understand how A is the correct answer. Can someone explain this approach step by step?
The ratio of alcohol to water in bottle A is 1: 3 , If the volume of solution in bottle A is X
The Volume of alcohol will be (1/4)* X = 0.25 X
Similarly the ratio of alcohol to water in bottle B is 4:1, If the volume of solution in bottle B is Y
The volume of alcohol will be (4/5) * Y = 0.8 Y
To find : Percentage of alcohol if the solutions of A and B are mixed
It will be \(\frac{( 0.25 * X + 0.8 * Y)}{(X + Y)}\) * 100
St 1 : X = Y
Value will become \(\frac{(0.25 * X + 0.8 * X)}{(X + X)}\) * 100
X will get cancelled in the numerator and denominator and a unique numerical value will result
Sufficient
St 2 : X + Y = 10
But if we substitute X = 3 and Y =7 in the general formula mentioned before we discussed St 1 ,we will get one value
If we substitute X = 5, and Y = 5 , we will get a different value
Not Sufficient
Choice A
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