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C and D are positive integers. If C^D = (1/C)^3D-8, Then C^D

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Joined: 05 May 2003
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C and D are positive integers. If C^D = (1/C)^3D-8, Then C^D [#permalink]

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17 May 2003, 08:53
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C and D are positive integers. If C^D = (1/C)^3D-8, Then C^D =?
1. C=2D
2. D= sqrt(C)

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SVP
Joined: 03 Feb 2003
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18 May 2003, 04:59
Also vote for D.
From the initial data D=2 and C>0
Thus, either set is OK

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SVP
Joined: 30 Oct 2003
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Location: NewJersey USA

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29 Jan 2004, 09:15
the Q is asking us to find the value of C^D. From either of the given conditions we can express C in terms of D only. Is this OK. We dont know the value of D here. How can we determine C^D ?

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29 Jan 2004, 09:23
Anand

C^D = C^(3D-8)

=> D = 3D-8
=> D = 4

I guess remaining steps are easy to follow . Let me know if u still have qns

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SVP
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29 Jan 2004, 16:21
I thought the equation was C^D = C^D = (1/C)^3D-8 which is different from
C^D = (1/C)^(3D-8)
Suddenly you have put the paranthesis around 3D-8. It completly changes the meaning.

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Senior Manager
Joined: 30 Aug 2003
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29 Jan 2004, 17:26
you mean to say that 3D-8 is only power to C but not for 1/C..i'm still confused
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shubhangi

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29 Jan 2004, 17:26
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C and D are positive integers. If C^D = (1/C)^3D-8, Then C^D

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