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Can A and can В are both right circular cylinders. The radiu [#permalink]
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17 Mar 2011, 14:46
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Can A and can В are both right circular cylinders. The radius of can A is twice the radius of can B, while the height of can A is half the height of can B. If it costs $4.00 to fill half of can B with a certain brand of gasoline, how much would it cost to completely fill can A with the same brand of gasoline? (A) $1 (B) $2 (C) $4 (D) $8 (E) $16
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Re: 2. (KP) Can A and can В are both right circular cylinders. T [#permalink]
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17 Mar 2011, 15:09
banksy wrote: 2. (KP) Can A and can В are both right circular cylinders. The radius of can A is twice the radius of can B, while the height of can A is half the height of can B. If it costs $4.00 to fill half of can B with a certain brand of gasoline, how much would it cost to completely fill can A with the same brand of gasoline? (A) $1 (B) $2 (C) $4 (D) $8 (E) $16 Let x be the radius of b and 2h be the height of B. Therefore, radius of A = 2x and height = h Vol of b = 3.14*x^2*2h Vol of a = 3.14*4x^2*h cost to fill half of B = $4 > cost to fill full B = $8 > 3.14*x^2*2h = 8 > 3.14*x^2*h = 4 > 4*(3.14*x^2*h) = $16 Ans E



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Re: 2. (KP) Can A and can В are both right circular cylinders. T [#permalink]
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19 Mar 2011, 01:57
B > pi * r^2*h A > pi * 4r^2 * h/2 = 2 * pi * r^2 * h So, Vol of 1/2 of can B = vol of 1/4 can A So can A will take 4 * 4 = $16 for gasoline.
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Re: 2. (KP) Can A and can В are both right circular cylinders. T [#permalink]
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19 Mar 2011, 02:52
banksy wrote: 2. (KP) Can A and can В are both right circular cylinders. The radius of can A is twice the radius of can B, while the height of can A is half the height of can B. If it costs $4.00 to fill half of can B with a certain brand of gasoline, how much would it cost to completely fill can A with the same brand of gasoline? (A) $1 (B) $2 (C) $4 (D) $8 (E) $16 Let radius of B be r and A be 2r vol of B=πr^2h vol of a=4πr^2h (radius= (2r)) == twice the volume of B To fill 1/2 of B it cost 4$ to fill B it cost 8 $ to fill 2b ie (a) it cost 16$



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Re: 2. (KP) Can A and can В are both right circular cylinders. T [#permalink]
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19 Mar 2011, 03:05
banksy wrote: 2. (KP) Can A and can В are both right circular cylinders. The radius of can A is twice the radius of can B, while the height of can A is half the height of can B. If it costs $4.00 to fill half of can B with a certain brand of gasoline, how much would it cost to completely fill can A with the same brand of gasoline? (A) $1 (B) $2 (C) $4 (D) $8 (E) $16 Volume of right circular cylinder = 2πr^2h Let Radius of Can A= 4 Height of can A = 2 Volume of Can A = 2*π*r^2*h = 2*π*4^2*2 = 64π Radius of can B = 2 Height of can B = 4 Volume of Can B= 2*π*r^2*h = 2*π*2^2*4 = 32π 1/2 of B= 32π/2=16π thus cost required to fill can A = (4/16π)*64π= $16 Ans E.
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Re: 2. (KP) Can A and can В are both right circular cylinders. T [#permalink]
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22 Sep 2013, 20:34
sorry guys the answer is $ 8. lets consider the radius of can A to be 2x. radius of can B to be x. let the height of can A be y. Let the height of can B be 2y. Volume of a can A (pie 4x^2y) Volume of can B (pie 2 x^2 y). Since volume of can B is exactly half of can A. It costs $8 to fill can A completely.



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Re: 2. (KP) Can A and can В are both right circular cylinders. T [#permalink]
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23 Sep 2013, 00:26
mohnish104 wrote: sorry guys the answer is $ 8. lets consider the radius of can A to be 2x. radius of can B to be x. let the height of can A be y. Let the height of can B be 2y. Volume of a can A (pie 4x^2y) Volume of can B (pie 2 x^2 y). Since volume of can B is exactly half of can A. It costs $8 to fill can A completely. Notice that we a re told that it costs $4.00 to fill half of can B. so the correct answer is E, not D. Can A and can В are both right circular cylinders. The radius of can A is twice the radius of can B, while the height of can A is half the height of can B. If it costs $4.00 to fill half of can B with a certain brand of gasoline, how much would it cost to completely fill can A with the same brand of gasoline?(A) $1 (B) $2 (C) $4 (D) $8 (E) $16 Volume of B = \(\pi{r^2}h\) Volume of A = \(\pi{(2r)^2}(\frac{h}{2})=2\pi{r^2}h\). Thus the volume of can A is twice the volume of cam B. If it costs $4.00 to fill half of can B, then it costs 4*$4=$16 to completely fill can A. Answer: E.
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Re: Can A and can В are both right circular cylinders. The radiu [#permalink]
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23 Sep 2013, 05:25
Thank you Bunuel. I guess the answer has been wrongly pointed out in the Kaplan tests.



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Re: Can A and can В are both right circular cylinders. The radiu [#permalink]
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Re: Can A and can В are both right circular cylinders. The radiu [#permalink]
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02 Feb 2016, 15:48
Hey guys,
one question. I first tried to pick some smart numbers. Apparently they weren't smart enough as I did not get the volume of cylinder A to be twice the volume of cylinder B. I picked 4 and 2 for radii and 3 and 6 for heights. Of course, if we pick 4 and 2 for radii and 2 and 4 for heights, we are fine. So my question then is, if I for whatever reason at the actual test decide to go with smart numbers strategy for such a problem, how can I avoid this mistake? What am I missing here?
Appreciate your help as always!
Best, Jay



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Re: Can A and can В are both right circular cylinders. The radiu [#permalink]
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02 Feb 2016, 23:31
MrSobe17 wrote: Hey guys,
one question. I first tried to pick some smart numbers. Apparently they weren't smart enough as I did not get the volume of cylinder A to be twice the volume of cylinder B. I picked 4 and 2 for radii and 3 and 6 for heights. Of course, if we pick 4 and 2 for radii and 2 and 4 for heights, we are fine. So my question then is, if I for whatever reason at the actual test decide to go with smart numbers strategy for such a problem, how can I avoid this mistake? What am I missing here?
Appreciate your help as always!
Best, Jay Nothing! These numbers are fine too. You probably messed up the calculations somewhere. Volume of a right circular cylinder \(= \pi*r^2*h\) Volume of can A \(= \pi * 4^2* 3 = 48* \pi\) Volume of can B \(= \pi * 2^2 * 6 = 24* \pi\) Volume of can A is twice the volume of can B. OF course, you can stick with radii as 2r and r and heights as h and 2h since you just need the comparative volumes of the two cans.
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Re: Can A and can В are both right circular cylinders. The radiu [#permalink]
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03 Feb 2016, 01:50
Oh boy, indeed I messed up the easy calculation. Hate those mistakes so much.
Thanks for clarification Karishma!
Best, Jay




Re: Can A and can В are both right circular cylinders. The radiu
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