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# Can anyone tell me the fastest approach to such questions

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Senior Manager
Joined: 19 Feb 2007
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Can anyone tell me the fastest approach to such questions [#permalink]

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29 Oct 2007, 22:17
00:00

Difficulty:

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Can anyone tell me the fastest approach to such questions
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SVP
Joined: 29 Aug 2007
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Re: PS: Set 27 Q 8 [#permalink]

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29 Oct 2007, 22:23
I would say E.
39/128 = 39/2^7.

the divisor is a power of 2, so it should end at terminating decimal.
Re: PS: Set 27 Q 8   [#permalink] 29 Oct 2007, 22:23
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