Blackbox wrote:
mikemcgarry,
Please correct my approach if need be.
Given that the objects are traveling in opposite directions. So, add their individual speeds.
Total Speed = 110mph
Distance between objects = 120 mi
Time = D/T => 120/110 = 12/11 = 1hr 9 mins (approx.)
Therefore, relative to the time when those objects began their travel, they will cross each other at approx 3:09pm
Now, it is also given that once they cross paths, they travel for another 45 mi. Prompt's asking how long it took to travel 45 mi away from each other.
We know their combined speed is 110 mph, distance is 45mi. So, calculate time taken to scale 45mi.
T = 45/110
T = 0.40 hrs (approx.) which is 24 minutes (approx.)
Therefore, adding these 24 mins to 3:09pm, the final result will be 3:33pm, which is B.
Is this approach OK?
sunita123 wrote:
Hello Blackbox,
i also solved in same way as you did. But i took relative velocity 12 (61-49) as they move in opposite direction for 45 miles after they cross each other. but i did not get the correct answer.
Dear
Blackbox &
sunita123,
I'm happy to respond.
Blackbox, your approach was fine but was not the most efficient method. When the velocities are in opposite directions, we add the velocities, regardless of whether they are approaching head-on or receding in opposite directions. Thus, it is the same pattern for both distances in this problem, so we can just add the distances and divide by the sum of the speeds:
(120 + 45)/110 = 165/110 = 15*11/110 = 15/10 = 1.5 hr
That would be the most efficient method of solution.
sunita123, my friend, I'm sorry to say that you don't understand relative velocity. Once again, for relative velocity, you ADD if the velocities are in opposite direction and only SUBTRACT if the velocities are in the same direction. It's not a one-size-fits-all formula.
Does this make sense?
Mike