It is currently 17 Dec 2017, 08:05

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

challenge 25 question 2

  post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
Manager
Manager
avatar
Joined: 05 Oct 2005
Posts: 199

Kudos [?]: 7 [0], given: 0

challenge 25 question 2 [#permalink]

Show Tags

New post 31 May 2006, 11:36
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

plz Explain your reasoning and approach to this one
Explanations given are not clear


how many integers divisible by 3 are there betwen 10! and 10!+20

6
7
8
9
10



thanks
_________________

when there is a will there is a way

best regards

Kudos [?]: 7 [0], given: 0

Intern
Intern
avatar
Joined: 29 Apr 2006
Posts: 14

Kudos [?]: [0], given: 0

 [#permalink]

Show Tags

New post 31 May 2006, 11:43
I will go with 7. And Explanation goes as

10! is divisible by 3
and between 10! and 10!+ 20 there are 6 integers divisible by 3 ( 10!+3, 10!+6, 10!+9, 10!+12, 10!+15, 10!+18)

So total 7 integers are there between 10! and 10!+20 that are divisible by 3.


Please correct me if iam wrong

Kudos [?]: [0], given: 0

CEO
CEO
User avatar
Joined: 20 Nov 2005
Posts: 2892

Kudos [?]: 337 [0], given: 0

Schools: Completed at SAID BUSINESS SCHOOL, OXFORD - Class of 2008
 [#permalink]

Show Tags

New post 31 May 2006, 12:06
7

10! is divisible by 3. Others are 10!+3, 10!+6........10!+18
_________________

SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008

Kudos [?]: 337 [0], given: 0

Manager
Manager
avatar
Joined: 10 May 2006
Posts: 186

Kudos [?]: 5 [0], given: 0

Location: USA
 [#permalink]

Show Tags

New post 31 May 2006, 13:14
I would say 6 since the problem says BETWEEN 10! and 10! + 20.

However, if it were inclusive of 10!, then the answer would be 7.

Kudos [?]: 5 [0], given: 0

Manager
Manager
avatar
Joined: 05 Oct 2005
Posts: 199

Kudos [?]: 7 [0], given: 0

 [#permalink]

Show Tags

New post 31 May 2006, 13:24
:-D thanks for urs explanation answer is 7 so it is inclusive i guess
_________________

when there is a will there is a way

best regards

Kudos [?]: 7 [0], given: 0

Director
Director
avatar
Joined: 17 Sep 2005
Posts: 901

Kudos [?]: 118 [0], given: 0

Re: challenge 25 question 2 [#permalink]

Show Tags

New post 03 Jun 2006, 03:33
mand-y wrote:
plz Explain your reasoning and approach to this one
Explanations given are not clear


how many integers divisible by 3 are there betwen 10! and 10!+20

6
7
8
9
10

thanks


I would go for 6.
It's between 10! and 10! +20.
There are 6 numbers between 1 and 20 which can be divisible by 3.

Regards,
Brajesh

Kudos [?]: 118 [0], given: 0

Re: challenge 25 question 2   [#permalink] 03 Jun 2006, 03:33
Display posts from previous: Sort by

challenge 25 question 2

  post reply Question banks Downloads My Bookmarks Reviews Important topics  

Moderator: chetan2u



GMAT Club MBA Forum Home| About| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.