GMAT Questions Chat Group

A+b+c+d=25
Atleast 3
A+2 +b+2+c+2+d+2= 25
A+b+c+d = 17
Non negative integral sol
16C3

Will be right angeled triangle
So sides will be pythagor triplets
From options
3 4 5
X = 3 or 4
Permiters is 4x
So X= 3 Y= 4

there-are-twenty-five-identical-marbles-to-be-divided-among-four-broth-297867.html

PS Question 1 - Aug 23

A, B, K start from the same place and travel in the same direction at speeds of 30km/hr, 40km/hr, 60km/hr respectively. B starts two hours after A. If B and K overtake A at the same instant, how many hours after A did K start?

A) 3
B) 4.5
C) 4
d) 5.5
e) 5

Source: Official Guide | Difficulty: Medium

DS Question 1 - Aug 23

What is the remainder when positive integer X is divided by 40?

(1) 3X + 30 leaves remainder 93 when divided by 120.
(2) 5X - 10 leaves remainder 15 when divided by 20.

Source: Experts Global | Difficulty: Medium

C is the correct option. When A starts at 30km/hr, A travels for 8 hrs to reach 240 km, B takes 6 hrs to travel the same distance since it started 2 hrs late. Going by the same logic, to reach 240 km, K will travel for 4 hrs indicating K started 4 hrs later than A.

Both statements are sufficient individually?

Sorry, S1 is sufficient but S2 is not

Statement 1 is only Sufficient.
Answer A.

St1: 3x+30=120m +93
x=40m+21 ; r=21

St2: 5x-10=20m+15
5x=20m+25
x=4m+5
x=4(m+1)+1
x=1,5,13,16....
so we get different remainder when x is divided by 40.

Let time taken by A to reach a distance where all 3 meet = T hours. Then time taken by B = T-2 hours. Let time taken by K = Z hours. Now Distance covered by A = 30T which will be equal to distance covered by B = 40(T - 2); On solving, T = 8. Hence distance covered by A in 8 hours = 30 * 8 = 240 kms which is equal to 60Z. Thus Z = 240/60 = 4 hours. Correct answer is C

how guys can someone solve this for me!

A certain amount of work can be completed by 20 people in 100 days, working 12 hours a day. 5 people started the work, and starting from the second day, 7 people joined at the beginning of each day. Every alternate day, starting from the third day, two people left at the beginning of that day. If each person worked for two hours per day, then what fraction of the work was not completed after 60 days? (Assume efficiency of each person is the same)

I wanted to write hi, less on braincells, ignore the how part please :’)

Hi guys, hope everyone is doing well today. I’m still new here. I was wondering where all the answer choices are for questions like this; what-is-the-value-of-xy-1-y-x-1-2-y-x-277001.html?fl=email#p2137522

I don’t see the selection of A, B, C, D or E like in other questions

That’s the standard Data Sufficiency question format, whose choices A-E are fixed (always this wording, always this sequence):
(A) Statement (1) ALONE is sufficient but statement (2) ALONE is not sufficient.
(B) Statement (2) ALONE is sufficient but statement (1) ALONE is not sufficient.
(C) BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
(D) EACH statement ALONE is sufficient.
(E) Statements (1) and (2) TOGETHER are not sufficient.

ohhhh, thank you so much!

Given that 20 people can complete the work in 100 days working 12 hours per day
So the total work = 20 * 100 * 12 = 24,000 person-hours
Initially 5 people started working and they worked 2 hours per day each
So in the first day they worked = 5 * 2 = 10 hours
From the second day, 7 more people joined each day
So from day 2 onwards, number of people = 5 + 7 = 12
They can work 2 hours each, so work done = 12 * 2 = 24 hours
From the third day, 2 people leave each alternate day while 7 people join every day
So on day 3, number of people = 12 + 7 - 2 = 17
They work 2 hours each, so work done = 17 * 2 = 34 hours
On day 4, number of people = 17 + 7 = 24
Work done = 24 * 2 = 48 hours
On day 5, number of people = 24 + 7 - 2 = 29
They work 2 hours each, so work done = 29 * 2 = 58 hours... On day 6, number of people = 29 + 7 = 36
Work done = 24 * 2 = 72 hours........ On analysing the pattern there are two Arithmetic Progressions here:

One with sequence as 10, 34, 58, ... with number of terms as 30 and common difference as 24... Thus Last term is = 10 + (30-1)*24 = 706; Hence Sum of these 30 terms = (10 + 706)*15 = 10740

Another series is 24, 48, 72, ... with number of terms as 30 and common difference as 24... Thus Last term is = 24 + (30-1)*24 = 720; Hence Sum of these 30 terms = (24 + 720)*15 = 11,160

Thus total work done = 10,740 + 11,160 person-hours = 21,900 person-hours

Hence fraction of work remaining after 60 days = (24000 - 21900)/24000 = 2100/24000 = 7/80

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Hi, you could initially find out the total hours it required to complete whole work. Then calculate the total hours for which people worked in 60 days and then find the fraction in terms of hours

PS Question 1 - Aug 26

Of the four-digit positive integers that are greater than 4000, how many have three digits that are equal to each other and one digit that is not equal to the other three?

A. 162
B. 215
C. 216
D. 240
E. 324

Source: GMAT Ninja | Difficulty: Hard

DS Question 1 - Aug 26

If k is a positive integer, is k a multiple of 10 ?

(1) k^2 + 1 is a prime number.
(2) 2k is divisible by 5

Source: GMAT Club Test | Difficulty: Hard

i’m getting 212 can you explain how did you get 215?