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Nov 11 - Data Sufficiency Question 1

Is | x - 1 | 0

Source: GMAT Club Tests | Difficulty Level: Hard
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Nov 11 - Data Sufficiency Question 1

Is | x - 1 | 0

Source: GMAT Club Tests | Difficulty Level: Hard
E
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Nov 11 - Data Sufficiency Question 1

Is | x - 1 | 0

Source: GMAT Club Tests | Difficulty Level: Hard
E
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Nov 11 - Problem Solving Question 1

The function g has the property that g(a) = g(b) for all real numbers a and b. What is the graph of y = g(x) in the xy-plane?

A. A parabola symmetric about the 𝑥-axis
B. A line with slope 0
C. A line with slope 1
D. A line with no slope
E. A semicircle centered at the origin

Source: Others (PS Butler Question) | Difficulty: Medium
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Nov 11 - Data Sufficiency Question 2

The infinite sequence a_1, a_2,…, a_n, … is such that a_{n} = a_{n-1} + a_{n - 2}, for all n > 2. What is the value of a_1 ?

(1) a_6 = 11

(2) a_9 = 17

Source: GMAT Club Tests (DS Butler Series) | Difficulty Level: Medium
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Nov 11 - Data Sufficiency Question 1

Is | x - 1 | 0

Source: GMAT Club Tests | Difficulty Level: Hard

kapil1995
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Nov 11 - Data Sufficiency Question 2

The infinite sequence a_1, a_2,…, a_n, … is such that a_{n} = a_{n-1} + a_{n - 2}, for all n > 2. What is the value of a_1 ?

(1) a_6 = 11

(2) a_9 = 17

Source: GMAT Club Tests (DS Butler Series) | Difficulty Level: Medium
E ?
Why do think the combination of statement 1 and statement 2 won’t work ?

Woohoo .. its Saturday !

Here is the Topic of the day

Link: Avoiding Traps in GMAT Quant Questions
Complied by : Bunuel | Published by : Veritas Prep
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Nov 12 - Data Sufficiency Question 1

10 students took a chemistry exam that was graded on a scale of 0 to 100. Five of the students were in Dr. Adams’ class and the other five students were in Dr. Brown’s class. Is the median score for Dr. Adams’ students greater than the median score for Dr. Brown’s students?

(1) The range of scores for students in Dr. Adams’ class was 40 to 80, while the range of scores for students in Dr. Brown’s class was 50 to 90.

(2) If the students are paired in study teams such that each student from Dr. Adams’ class has a partner from Dr. Brown’s class, there is a way to pair the 10 students such that the higher scorer in each pair is one of Dr. Brown’s students.

Source: Manhattan Prep | Difficulty : Medium
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Nov 12 - Problem Solving Question 1

The first six positive integers are used once to form two three-digit numbers. What is the minimum possible difference between the two numbers formed?

A. 87
B. 78
C. 69
D. 60
E. 47

Source: Expert’s Global | Difficulty : Hard
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Nov 12 - Data Sufficiency Question 2

If A and B are integers, is N an even integer?

(1) 11A + 4B = N
(2) 5A – 4B = 2N

Source: GMATPrepNow | Difficulty: Hard
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Nov 12 - Data Sufficiency Question 2

If A and B are integers, is N an even integer?

(1) 11A + 4B = N
(2) 5A – 4B = 2N

Source: GMATPrepNow | Difficulty: Hard
Answer: C

Given: A, B are integers
To determine: Is N an even integer?

(1) 11A + 4B = N
4B is always EVEN => N = 11A + Even
If A: Odd, then N = Odd + Even = Odd
If A: Even, then N = Even + Even = Even

NOT SUFFICIENT

(2) 5A - 4B = 2N
2N is always even
So, since we do not know exactly values of A and B, we cannot say whether LHS is even or odd multiple of 2
N could either be ODD or EVEN

NOT SUFFICIENT

Both Statements Together:

Adding both statements together
16A = 3N
Now, we know that 16A will always be EVEN
=> 3N = Even and since 3 is Odd, so N must be EVEN

SUFFICIENT

Answer: C
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Nov 12 - Data Sufficiency Question 2

If A and B are integers, is N an even integer?

(1) 11A + 4B = N
(2) 5A – 4B = 2N

Source: GMATPrepNow | Difficulty: Hard
Answer: C

Given: A, B are integers
To determine: Is N an even integer?

(1) 11A + 4B = N
4B is always EVEN => N = 11A + Even
If A: Odd, then N = Odd + Even = Odd
If A: Even, then N = Even + Even = Even

NOT SUFFICIENT

(2) 5A - 4B = 2N
2N is always even
So, since we do not know exactly values of A and B, we cannot say whether LHS is even or odd multiple of 2
N could either be ODD or EVEN

NOT SUFFICIENT

Both Statements Together:

Adding both statements together
16A = 3N
Now, we know that 16A will always be EVEN
=> 3N = Even and since 3 is Odd, so N must be EVEN

SUFFICIENT

Answer: C
Great Explanation ! :)
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Nov 12 - Problem Solving Question 1

The first six positive integers are used once to form two three-digit numbers. What is the minimum possible difference between the two numbers formed?

A. 87
B. 78
C. 69
D. 60
E. 47

Source: Expert’s Global | Difficulty : Hard
We need to form two 3 digit numbers with {1,2,3,4,5,6} such that difference is the least

So, first of all, we can start by thinking that one of the number will be 400-something and the other 300-something because in any other case, difference will be bigger than in this one

So, one number starts with 4 and one with 3: Remaining digits = 1,2,5,6
Since we want the difference to be the LEASE, we club the 4 with the lower two number and the 3 with the higher two numbers

412 - 365 = 47

Answer: E
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Nov 12 - Data Sufficiency Question 1

10 students took a chemistry exam that was graded on a scale of 0 to 100. Five of the students were in Dr. Adams’ class and the other five students were in Dr. Brown’s class. Is the median score for Dr. Adams’ students greater than the median score for Dr. Brown’s students?

(1) The range of scores for students in Dr. Adams’ class was 40 to 80, while the range of scores for students in Dr. Brown’s class was 50 to 90.

(2) If the students are paired in study teams such that each student from Dr. Adams’ class has a partner from Dr. Brown’s class, there is a way to pair the 10 students such that the higher scorer in each pair is one of Dr. Brown’s students.

Source: Manhattan Prep | Difficulty : Medium

gmatophobia
Nov 12 - Problem Solving Question 1

The first six positive integers are used once to form two three-digit numbers. What is the minimum possible difference between the two numbers formed?

A. 87
B. 78
C. 69
D. 60
E. 47

Source: Expert’s Global | Difficulty : Hard

gmatophobia
Nov 12 - Data Sufficiency Question 2

If A and B are integers, is N an even integer?

(1) 11A + 4B = N
(2) 5A – 4B = 2N

Source: GMATPrepNow | Difficulty: Hard
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Nov 12 - Data Sufficiency Question 1

10 students took a chemistry exam that was graded on a scale of 0 to 100. Five of the students were in Dr. Adams’ class and the other five students were in Dr. Brown’s class. Is the median score for Dr. Adams’ students greater than the median score for Dr. Brown’s students?

(1) The range of scores for students in Dr. Adams’ class was 40 to 80, while the range of scores for students in Dr. Brown’s class was 50 to 90.

(2) If the students are paired in study teams such that each student from Dr. Adams’ class has a partner from Dr. Brown’s class, there is a way to pair the 10 students such that the higher scorer in each pair is one of Dr. Brown’s students.

Source: Manhattan Prep | Difficulty : Medium
To determine: Median(A) > Median (B)?

(1) A: 40,50,60,70,80 & B: 50,60,70,80,90 (In this case, answer is NO)
A: 40,80,80,80,80 & B: 50,60,70,80,90 (In this case, answer is YES)
NOT SUFFICIENT

(2) This statement basically says that each score of Dr Brown

Sorry, enter by mistake, let me re-type

To determine: Median(A) > Median (B)?

(1) A: 40,50,60,70,80 & B: 50,60,70,80,90 (In this case, answer is NO)
A: 40,80,80,80,80 & B: 50,60,70,80,90 (In this case, answer is YES)
NOT SUFFICIENT

(2) This statement basically says that each score of Dr Brown’s class > each score in Dr. Adam’s class
If each score is greater than each score in the other, then even the median score is Dr Brown’s class > Median score of Dr. Adams’ class
SUFFICIENT

Answer B
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Nov 13 - Problem Solving Question 1

Within equilateral triangle A, circle B is inscribed; within circle B, square C is inscribed; within square C, circle D is inscribed; within circle D, square E is inscribed; within square E, circle F is inscribed; finally, within circle F, equilateral triangle G is inscribed.

What is the ratio of the area of triangle A to the area of triangle G?

(A) 4 √2 : 1
(B) 8 : 1
(C) 8 √2 : 1
(D) 16 : 1
(E) 16 √2 : 1

Source: Manhattan Prep | Difficulty : Hard
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Nov 13 - Problem Solving Question 2

The angles in a triangle are x, 3x, and 5x degrees. If a, b, and c are the lengths of the sides opposite to angles x, 3x, and 5x respectively, then which of the following must be true?

I) c > a + b
II) c : a : b = 10 : 6 : 2
III) c^2 > a^2 + b^2

Source: GMAT Club Tests | Difficulty Level: Hard
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