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Answer is D, Each statement alone is sufficient right?
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do-both-sufficient-statements-provide-the-same-answer-in-a-ds-question-135812.html

Explained here by bunel.

You should get both answers as 3. If you are not getting then I think you are doing something wrong with second statement. I think second statement is not sufficient. Answer should be A.
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A sequence a_n defined such that a_{n} = a_{n-1} - a_{n-2} ,where n are integers greater than 2. What is the value of a_5 ?

(1) a_{4} - a_{3} = 3
(2) a_{14} = 1

How is option 2 sufficient

A sequence \(a_n\) defined such that \(a_{n} = a_{n-1} - a_{n-2}\), where n is a positive integer greater than 2. What is the value of \(a_5\)?

    \(a_{3} = a_{2} - a_{1}\);
    \(a_{4} = a_{3} - a_{2} = (a_{2} - a_{1}) - a_{2} = -a_{1}\);
    \(a_{5} = a_{4} - a_{3} = (-a_{1}) - (a_{2} - a_{1}) = -a_{2}\);
    \(a_{6} = a_{5} - a_{4} = (-a_{2}) - (-a_{1})=-(a_{2} - a_{1}) = -a_{3}\);
    \(a_{7} = a_{6} - a_{5} = -(a_{2} - a_{1}) - (-a_{2})=a_{1} = -a_{4}\);
    \(a_{8} = a_{7} - a_{6} = a_{1} - (a_{1} - a_{2})=a_{2} = -a_{5}\);
    and so on.

(1) \(a_{4} - a_{3} = 3\)

Above we we got that \(a_{5} = a_{4} - a_{3}\), hence \(a_{5} = 3\). Sufficient.

(2) \(a_{14} = -3\)

\(a_{14} = -a_{11}=a_8=-a_5=-3\). Hence \(a_{5} = 3\). Sufficient.

Answer: D.
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A sequence \(a_n\) defined such that \(a_{n} = a_{n-1} - a_{n-2}\), where n is a positive integer greater than 2. What is the value of \(a_5\)?
    \(a_{3} = a_{2} - a_{1}\); \(a_{4} = a_{3} - a_{2} = (a_{2} - a_{1}) - a_{2} = -a_{1}\); \(a_{5} = a_{4} - a_{3} = (-a_{1}) - (a_{2} - a_{1}) = -a_{2}\); \(a_{6} = a_{5} - a_{4} = (-a_{2}) - (-a_{1})=-(a_{2} - a_{1}) = -a_{3}\); \(a_{7} = a_{6} - a_{5} = -(a_{2} - a_{1}) - (-a_{2})=a_{1} = -a_{4}\); \(a_{8} = a_{7} - a_{6} = a_{1} - (a_{1} - a_{2})=a_{2} = -a_{5}\); and so on.
(1) \(a_{4} - a_{3} = 3\) Above we we got that \(a_{5} = a_{4} - a_{3}\), hence \(a_{5} = 3\). Sufficient. (2) \(a_{14} = -3\) \(a_{14} = -a_{11}=a_8=-a_5=-3\). Hence \(a_{5} = 3\). Sufficient. Answer: D.
So answer is D when a14 = -3. What if a14 = 1. In that case, from both statements we are getting an answer but a different one. So will the question becomes invalid or we answer A or D?
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Bunuel
A sequence \(a_n\) defined such that \(a_{n} = a_{n-1} - a_{n-2}\), where n is a positive integer greater than 2. What is the value of \(a_5\)?
    \(a_{3} = a_{2} - a_{1}\); \(a_{4} = a_{3} - a_{2} = (a_{2} - a_{1}) - a_{2} = -a_{1}\); \(a_{5} = a_{4} - a_{3} = (-a_{1}) - (a_{2} - a_{1}) = -a_{2}\); \(a_{6} = a_{5} - a_{4} = (-a_{2}) - (-a_{1})=-(a_{2} - a_{1}) = -a_{3}\); \(a_{7} = a_{6} - a_{5} = -(a_{2} - a_{1}) - (-a_{2})=a_{1} = -a_{4}\); \(a_{8} = a_{7} - a_{6} = a_{1} - (a_{1} - a_{2})=a_{2} = -a_{5}\); and so on.
(1) \(a_{4} - a_{3} = 3\) Above we we got that \(a_{5} = a_{4} - a_{3}\), hence \(a_{5} = 3\). Sufficient. (2) \(a_{14} = -3\) \(a_{14} = -a_{11}=a_8=-a_5=-3\). Hence \(a_{5} = 3\). Sufficient. Answer: D.
So answer is D when a14 = -3. What if a14 = 1. In that case, from both statements we are getting an answer but a different one. So will the question becomes invalid or we answer A or D?

Remember, on the GMAT, two data sufficiency statements always provide true information, and these statements never contradict each other or the stem. If the statements contradict each other, then, as per GMAT standards, the question is flawed. Hence, for the options not to contradict, \(a_{14}\) must be -3 in statement (2). Alternatively, if \(a_{14} = 1\), then in statement (1), \(a_{4} - a_{3}\) must be -1. In either case, though, each statement is sufficient on its own.
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Can someone please help me with these two questions?
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Can someone please help me with these two questions?
Is it π-2/ π for 20?
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Any solutions for this?
probability-424712.html
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Idk if it right but what i did is

found out probability of getting award is 3/8

and probably of 2 women getting award become 2/4*3/8 + probability of 3 women getting award is 3/4*3/8

result is 15/32 which is like 1/2

we cant award more than 3 women
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8 people need to be selected for 3 positions. So 56 ways .
2 women 1 men - 24
3 women 0 men - 4
Probability = 28/56 = 1/2. Lemme know if it’s wrong
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Four men and four women participated in a dance competition. Top three performers were awarded a gold coin, a silver coin, and a bronze coin, respectively. If there were no ties, what is the probability that at least two women were awarded?

A. 1/4
B. 1/3
C. 1/2
D. 3/4
E. 4/5

    P(at least two women) = P(two women) + P(three women) =

    = 4C2*4C1/8C3 + 4C3/8C3 =

    = 6*4/56 + 4/56 =

    = 1/2.

Answer: C.

Alternatively, note that we can have the following four cases:

    WWW
    WWM

    WMM
    MMM

We need to find the combined probability of the green events. Since there are an equal number of men and women, because of the symmetry, the probability of the green events equals the probability of the red events. And since their sum is 1, then the probability of each, red and green events, is 1/2.

Answer: C.
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Data Sufficiency Butler: January 2024
January 22DS 1DS 2
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Hi, can anyone help me solve this question? And what category/type of math question is this?
"Of the three-digit positive integers, how many have 0 in at least one digit."
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