GMAT Questions Chat Group

PS Question 1 - Nov 25

Peter invests $100,000 in an account that pays 12% annual interest: the interest is paid once, at the end of the year. Martha invests $100,000 in an account that pays 12% annual interest, compounding monthly at the end of each month. At the end of one full year, compared to Peter’s account, approximately how much more does Martha’s account have?

A. Zero
B. $68.25
C. $682.50
D. $6825.00
E. $68250.00

Source: Magoosh | Difficulty: Hard

PS Question 1 - Nov 27

Peter invests $100,000 in an account that pays 12% annual interest: the interest is paid once, at the end of the year. Martha invests $100,000 in an account that pays 12% annual interest, compounding monthly at the end of each month. At the end of one full year, compared to Peter’s account, approximately how much more does Martha’s account have?

A. Zero
B. $68.25
C. $682.50
D. $6825.00
E. $68250.00

Source: Magoosh | Difficulty: Hard

Hate interest problems. I suck at them.
This is what I did for this one though
Peter interst: 12000
now find a pattern for martha:
Her interest is compounded monthly, so to find each months interest you divide by 12, so each month pays 1% interest.
Month 1 interest: 100000*0.01=1000
Moth 2 interest: 101000*0.01=1010
Month 3: 102100*0.01=1021
We can see that each month, she earns 10 in extra interest aprox. therefore we can make the following equation:
Martha Interest = 1000+1010+1020+1030+...1120. Which sums to around 12700. So 700 extra. Closest answer is C.

If one was low on time, you could easily guess this right. A cannot be correct, since martha will surely earn more. 68 is possible, but too small. C seems okay. E is clearly far too large, and between D and C, C seems more reasonable.
The answers are pretty far apart here, so you can somewhat use logic.

PS Question 2 - Nov 27

Rita and Sam play the following game with n sticks on a table. Each must remove 1, 2, 3, 4 or 5 sticks at a time on alternate turns, and no stick that is removed is put back on the table. The one who removes the last stick (or sticks) from the table wins. If Rita goes first, which of the following is a value of n such that Sam can always win no matter how Rita plays?

A. 7
B. 10
C. 11
D. 12
E. 16

Source: Official Guide | Difficulty: Hard

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GMAT Quant Practice Questions - Geometry: Triangles, Circles, & Polygons

[url]https://www.youtube.com/watch?v=CvGNGTYwJ6A[\url]

Starts in an hour ...

9:30am NY | 2:30pm London | 8pm Mumbai

GMAT Quant Practice Questions - Geometry: Triangles, Circles, & Polygons

Youtube link - Click here

I found it very tough ...Its indication that I need to improvise on these topics

Hey!

No worries. You may want to check out GMAT Club Math book to brush up few concepts. It has great content on Geometry. Additionally, I have posted few articles by e-GMAT that you might find useful. Links to the resources are given below.

GMAT Club Math Book
Properties of Quadrilaterals-by eGMAT
Common Mistakes in Geometry Questions-by eGMAT
Bonus:
Notes by selberenova
Happy Learning ! :thumbsup:

DS Question 1 - Nov 28

A pentagon with 5 sides of equal length and 5 interior angles of equal measure is inscribed in a circle. Is the perimeter of the pentagon greater than 26 centimeters?

(1) The area of the circle is 16π square centimeters.
(2) The length of each diagonal of the pentagon is less than 8 centimeters.

Source: Official Guide | Difficulty : Hard

C...not sure

Do you want to share your working ? The pentagon is a regular pentagon, hence I believe we can use that logic to arrive at the answer.

PS Question 1 - Nov 28

If x and y are integers greater than 3, and 15y – 11x = 8, what is the least possible value of x+y?

A) 12
B) 16
C) 26
D) 30
E) 34

Source: GMATPrepNow | Difficulty : Medium

1st solution (2,2)

second solution (13,17)

since both x,y > 3. second solution be will be valid , hence y+x=13+17=30

PS Question 1 - Nov 28

If x and y are integers greater than 3, and 15y – 11x = 8, what is the least possible value of x+y?

A) 12
B) 16
C) 26
D) 30
E) 34

Source: GMATPrepNow | Difficulty : Medium[/quote]



1st solution (2,2)

second solution (13,17)

since both x,y > 3. second solution be will be valid , hence y+x=13+17=30

1st solution (2,2)

second solution (13,17)

since both x,y > 3. second solution be will be valid , hence y+x=13+17=30 [/quote]
D.30

PS Question 2 - Nov 28

x and y are positive integers and 5x + 4y = 240. If x is a multiple of 3, then y could be a multiple of which of the following?

I. 6
II. 9
III. 15

(A) I only
(B) II Only
(C) II & III
(D) I & III
(E) I, II, & III

Source: Magoosh | Difficulty: Hard

DS Question 2 - Nov 28

If x is a positive integer greater than 1, what is the value of x?

(1) 2x is a common factor of 18 and 24
(2) x is a factor of 6

Source: Official Guide | Difficulty: Medium

1) 18 has factors 18, 9, 6, 3, 1
24 has factors 24, 12, 8, 6, 4, 3. Of these, only 6 and 3 are common. Because 2x has to be integer, 3 is not possible as xwould be fraction, 2x=6, x=3. Sufficient
2) 6 has factors 6,3,2,1. X can be 3,2,6. Insuff.
A

x=3k
5(3k)+4y=240
15k=240-4y
k=4(60-y)/15
now test cases
k=4(60-6z)/15
4*6(10-z)/15
if z=5, k is integer. Possible
elim B.
k=4(60-15z)/15
k=4*15(4-z)/15. Clearly possible.
k=4(60-9z)/15
k=4*3(20-3z)/15
z=5, k is integer. possible.
Should be E.

A

Common factor of 18 and 24 are 1,2,3,6 but thiscommon factor is 2x meaning multiple of 2 so 2x can be 2 or 6...so x will be 1 or 3 but x is greter than 1 so x=3..statement 1 is sufficient...statment 2 is not sufficient

PS Question 1 - Nov 29

55% of people like to travel by bus, 37% of people like to travel by auto and 25% of people like to travel by taxi. Also, 30% of people like to travel by at least two vehicles from bus, taxi, and auto, while 6% of people like to travel by all the three, then how many people like to travel by at least one of the three vehicles?

A. 94%
B. 93%
C. 87%
D. 81%
E. 51%

Source: Expert’s Global | Difficulty: Hard