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sohailasif786
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GMAT Questions Chat Group 06 Jul 2024, 01:01
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I think 12

Fix ab then remaining can be arranged in 3! Ways

But ab also can be arranged in 2! Ways

so 2!x3!

But this is a circular permutation question I hope m right
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Barnali123456
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GMAT Questions Chat Group 06 Jul 2024, 01:31
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Can anyone please solve this question? And option (d) is given in the answer key.
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pranjalshah
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GMAT Questions Chat Group 06 Jul 2024, 02:04
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fast way would be plugging in values. I put 5 and it didn’t satisfy. So B and C are gone. I put -5 and it satisfied. So A is also gone. D remains and thats the answer.
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aaryavashisth
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GMAT Questions Chat Group 06 Jul 2024, 02:15
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pranjalshah
fast way would be plugging in values. I put 5 and it didn’t satisfy. So B and C are gone. I put -5 and it satisfied. So A is also gone. D remains and thats the answer.
any specific reason to 5 only?
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GMAT Questions Chat Group 06 Jul 2024, 02:59
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Alex55
A large cube consists of 216 small identical cubes. What is the number of small cubes that do not have a face that is part of a face of the large cube?

A. 54

B. 58

C. 64

D. 76

E. 86
The bigger cube has side 6 units (say meters for example). This is essentially 216 small cubes of 1 m^3 volume.
Inner cubes (that do not have a face as part of the face of the larger cube form a smaller cube of 6 - 2 = 4 units. Total number of such cubes = 4^3 = 64. I have shown one cross section (top view) of the cube to visualize this.
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HarshavardhanR
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GMAT Questions Chat Group 06 Jul 2024, 03:24
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I see that the conventional way of solving has been shown beautifully by Mohit. Let me elaborate on how we can use the choices to solve this question.

The key is to take values that allow you to test between the choices. These are not random choices.

Some examples:
1) Choice C (2, inf) does not include 0. if we plug x = 0 and see, the inequality is still satisfied, then x= 0 is a valid value. Then, choice C can be rejected.
2) Choice D would include a value like x = -3 (or -5 or -6, etc.) but not choice A, B, D. If we plug x = -3, the inequality is still satisfied. Choices A, B, and C can be rejected :). Choice D is the answer.
3) Similar.
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pranjalshah
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GMAT Questions Chat Group 06 Jul 2024, 04:21
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aaryavashisth
any specific reason to 5 only?
nope.. thats the first number that came to my mind lol
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Krish13tss
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GMAT Questions Chat Group 06 Jul 2024, 04:54
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Hey guys, I have a query that, does pure algebra questions like~ Is A<0, etc removed from gmat ?
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Bunuel
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GMAT Questions Chat Group 06 Jul 2024, 05:17
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Krish13tss
Hey guys, I have a query that, does pure algebra questions like~ Is A<0, etc removed from gmat ?
­From DS, yes. PS still has pure algebra questions.

Pure algebraic questions are no longer a part of the DS syllabus of the GMAT.

DS questions in GMAT Focus encompass various types of word problems, such as:

  • Word Problems
  • Work Problems
  • Distance Problems
  • Mixture Problems
  • Percent and Interest Problems
  • Overlapping Sets Problems
  • Statistics Problems
  • Combination and Probability Problems

While these questions may involve or necessitate knowledge of algebra, arithmetic, inequalities, etc., they will always be presented in the form of word problems. You won’t encounter pure "algebra" questions like, "Is x > y?" or "A positive integer n has two prime factors..."

Check GMAT Syllabus for Focus Edition

Hope it helps.­
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Krish13tss
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GMAT Questions Chat Group 06 Jul 2024, 05:20
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Thanks for clarifying! ❤️
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Mandhana
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GMAT Questions Chat Group 06 Jul 2024, 05:34
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There are three clubs — A, B and C in a colony. Each of the 350 people of the colony is a member of at least one of
the three clubs. 50 people are members of all the three clubs and 100 people are members of exactly two clubs. 210
people are members of club C, while 90 among them are members of club C only.200 people are members of club A, then what is the maximum possible number of people who are members of only
club B?
(a) 50 (b) 60 (c) 80 (d) 100
14. If 130 people are members of club B then what is the minimum possible number of people who are members of both
the clubs A and C?
(a) 20 (b) 70 (c) 80 (d) 30
Any one can solve it please
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Mandhana
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GMAT Questions Chat Group 06 Jul 2024, 06:34
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Can you show me how you solve it.please
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Vivek77
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GMAT Questions Chat Group 06 Jul 2024, 08:08
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1) For b to be max, a should be minimum and e has to be maximum
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Mandhana
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Can you please tell me how you get a+d+g+e = 200
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Vivek77
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GMAT Questions Chat Group 06 Jul 2024, 09:33
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200 members are from Club A

is the answers correct?
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Mandhana
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GMAT Questions Chat Group 06 Jul 2024, 09:44
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Answer is correct. Thank you
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vishallchoudhary
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GMAT Questions Chat Group 06 Jul 2024, 20:25
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How did you decide to use the (A+B+C+D+E+F+G=350) formula instead of (A+B+C-2G-(D+E+F)=350)?
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HarshavardhanR
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GMAT Questions Chat Group 06 Jul 2024, 22:42
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Mandhana
There are three clubs — A, B and C in a colony. Each of the 350 people of the colony is a member of at least one of
the three clubs. 50 people are members of all the three clubs and 100 people are members of exactly two clubs. 210
people are members of club C, while 90 among them are members of club C only.200 people are members of club A, then what is the maximum possible number of people who are members of only
club B?
(a) 50 (b) 60 (c) 80 (d) 100
14. If 130 people are members of club B then what is the minimum possible number of people who are members of both
the clubs A and C?
(a) 20 (b) 70 (c) 80 (d) 30
Any one can solve it please
I got 1)60. I can also see why 2)70 seems to make sense. But I am not so sure about that second question though. Unless I have made an error somewhere, even the correct answer will not fit all the conditions. Happy to be corrected if I am wrong here.
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anuraggogoi
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GMAT Questions Chat Group 06 Jul 2024, 23:04
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Anyone who have bought the gmat official guide???
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vishallchoudhary
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GMAT Questions Chat Group 06 Jul 2024, 23:28
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How did you decide to use the (A+B+C+D+E+F+G=350) formula instead of (A+B+C-2G-(D+E+F)=350)?
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