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RahulKumarSinha
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Hello guys. 2k19 grad with 2.9 gpa ,2 gap years and 3 years of work ex. What are the chances of me getting an offer from insead / LBS if i score >760 on GMAT?
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Quite aspirational to get a >760.
I would suggest get a profile review done with some admission consultant and find things that can help with the gap years and GPA.
>685/>695 should be a good enough score to have GMAT aspect taken care of.
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Hi does anyone remember the remainder thereom, where if x is divided by 21 and leaves a remainder of 7, and when x is divided by 25 leaves a remainder of 7, how to use LCM in such cases.
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are there any more rules on remainder theorm or number theory which i can learn have been struggling on these kind of questions
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arjitt
are there any more rules on remainder theorm or number theory which i can learn have been struggling on these kind of questions
LCM(X,Y)*HCF(X,Y)=X*Y

arjitt
are there any more rules on remainder theorm or number theory which i can learn have been struggling on these kind of questions
Number of factors is an odd number in case of perfect squares. For the rest ,it is an even number
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hi, could someone please help me with the solution of this?
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Hi Saurav what if the remainders were different
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aayushimehta12
Hi Saurav what if the remainders were different
Suppose the question was framed as x leave remainder 6 when divided by 25 and 7 when divided by 21.

Then, x=25m+6 and x=21n+7
This implies that 25m+6=21n+7

25m-21n=1
one solution to this linear equation is m=5 and n=6

This implies that m=21a+5 and n=25b+6

You can substitute in any of the first equations we wrote for x in the beginning to find solution.
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I understood till 25m-21n=1, beyond that I a confused

*I am
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aayushimehta12
I understood till 25m-21n=1, beyond that I a confused
25m-21n=1

This means that

25m-1=21n

21m+4m-1=21n

We know that m and n are natural numbers and there are infinitely many solutions to this linear equation. To find on such solution, we try to reduce coefficient of any one variable. In this case "m"

To find one value of "n" in the above equation, we need only find one "m" for which
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500 households - The number of Tvs in each household is what constitutes the numbers in the set.

Median number of TVs = (Number of TVs in 250th house + number of TVs in 251st house)/2.

0 Tvs -> 1% of 500 = 5
1 Tv -> 50% of 500 = 250. So, from 6th house till the 255th house, each one has 1 TV. This is all we need to find median.

#Tvs in 250th house -> 1
#Tvs in 251st house -> also 1.

Median required = 1 (i.e. (1+1)/2). Choice A.
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Sure thing. carry on!
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Have yoy registered for the BIGGEST GMAT competition of the year?

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Anyone pls help me with this one…….. A family has 5 children, what is the probability that there are 3 boys and 2 girls among the children?
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is boy and girl are equally likely if yes then 5C3 (1/2)^5
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what options are available??
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@natasha your answer is incorrect
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