Priya.1998
Pipe A and B can fill a tank alone in 48 hours and 24 hours respectively. Another Pipe C can empty the same tank alone in 36 hours. In an empty tank for the first hour, Pipe A is opened alone, second hour pipe B is opened alone, third hour pipe C is opened alone. This process is continued until the tank is filled. Then Pipe B is opened for how many hours?
Given: Pipe
A fills the tank alone in 48 hours.
Pipe B fills the tank alone in 24 hours.
Pipe C empties the tank alone in 36 hours.
In the first hour,only Pipe A is opened, so it fills 1/48th of the tank.
In the second hour, only Pipe B is opened, so it fills 1/24th of the tank.
In the third hour, only Pipe C is opened, so it empties 1/36th of the tank.
We can observe that in the first three hours, the net amount of water filled in the tank is:
1/48 - 1/24 - 1/36 = (1/48) - (2/48) - (3/48) = -4/48 = -1/12
Since the tank is initially empty, the net amount of water in the tank after the first three hours is negative, which means the tank is not filled yet. Let’s assume that after x hours, the tank is filled.
We can write the equation as: (x/48) - (x/24) - (x/36) = 1
Simplifying the equation, we get: (3x - 6x - 4x) / (48 * 24 * 36) = 1 -7x / (48 * 24 * 36) = 1
Solving for x, we get: x = -48 * 24 * 36 / 7
Since x represents the number of hours, it cannot be negative.
Therefore, we can ignore the negative sign and calculate the value of x as: x = 48 * 24 * 36 / 7 = 82971.4286 hours
Since x represents the number of hours, it cannot be in decimal form.
Therefore, we round it up to the nearest whole number, which is 82972 hours.
To find the number of hours Pipe B is opened, we subtract the first three hours from the total time: 82972 - 3 = 82969 hours Therefore, Pipe B is opened for 82969 hours, which is equivalent to 28 hours and 10 minutes.