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Manager
Joined: 29 Apr 2003
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26 Oct 2003, 16:22
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

I find do not quite get the answer from OG for the attached question.

From OG, ... the number of rotations per second of the larger rim is 28/35
times the number of rotations of the smaller rim.

Does anyone has a solution with a simplified workings?
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Intern
Joined: 17 Aug 2003
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27 Oct 2003, 12:42
smaller rim makes x revs/sec which is 60x revs/min

the smaller rim is only 28/35 = 4/5 the size of the larger rim

therefore when the smaller rim makes 60x revs in a minute and they are spining at the same speed (in terms of movement). the larger rim will make (4/5)*60x revs in one minute.

at least that's how i did it.
27 Oct 2003, 12:42
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