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Coins are dropped into a toll box so that the box is being

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fiendex
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Coins are dropped into a toll box so that the box is being [#permalink] New post   05 Feb 2012, 17:15
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Coins are dropped into a toll box so that the box is being filled at the rate of approximately 2 cubic feet per hour. If the empty rectangular box is 4 feet long, 4 feet wide, and 3 feet deep, approximately how many hours does it take to fill the box?

A) 4
B) 8
C) 16
D) 24
E) 48
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D
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Re: Coins are dropped into a toll box so that the box is being [#permalink] New post   23 Aug 2016, 12:58
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volume of the box = 4 * 4 * 3 = 48 cu ft
rate at which the box is filled = 2 cu ft
time required = 48/2 = 24 hrs
correct answer - D
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Re: Coins are dropped into a toll box so that the box is being [#permalink] New post   11 Mar 2020, 10:33
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fiendex wrote:
Coins are dropped into a toll box so that the box is being filled at the rate of approximately 2 cubic feet per hour. If the empty rectangular box is 4 feet long, 4 feet wide, and 3 feet deep, approximately how many hours does it take to fill the box?

A) 4
B) 8
C) 16
D) 24
E) 48


The volume of the box is 4 x 4 x 3 = 48 cubic feet, so it will take approximately 48/2 = 24 hours to fill the box.

Answer: D
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Re: coins are dropped into a toll box so that the box is being [#permalink] New post   05 Feb 2012, 17:54
fiendex wrote:
coins are dropped into a toll box so that the box is being filled at the rate of approximately 2 cubic feet per hour. If the empty rectangular box is 4 feet long, 4 feet wide, and 3 feet deep, approximately how many hours does it take to fill the box?

A) 4
B) 8
C) 16
D) 24
E) 48


For finding the rate at which the box will be full we need to find the volume of the box , the volume of a rectangular cuboid = length*width*ht/depth= 4*4*3=48 cu.ft

This box is getting filled at the rate of 2 cu.ft per hour. Therefore, to fill the complete box having the volume 48 cu.ft it will take --48/2= 24 hours ie option D.
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Re: Coins are dropped into a toll box so that the box is being filled at [#permalink] New post   26 Feb 2022, 10:19
Bunuel wrote:
Coins are dropped into a toll box so that the box is being filled at the rate of approximately 2 cubic feet per hour. If the empty rectangular box is 4 feet long, 4 feet wide and 3 feet deep, approximately how many hours does it take to fill the box?

(A) 2
(B) 8
(C) 16
(D) 24
(E) 48


Time = Volume / Speed

\(= \frac{4*4*3}{2}=24 \) hrs.

Ans D
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Re: Coins are dropped into a toll box so that the box is being filled at [#permalink] New post   26 Feb 2022, 11:00
Fill Rate: A volume of 2 cubic feet for every hour that elapses.

Volume to fill:

4 x 4 x 3 = 48 cubic feet

Then 48 :2 = 24 hours

Answer D
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Re: Coins are dropped into a toll box so that the box is being filled at [#permalink] New post   16 Jun 2022, 02:41
Coins are dropped into a toll box so that the box is being filled at the rate of approximately 2 cubic feet per hour. If the empty rectangular box is 4 feet long, 4 feet wide and 3 feet deep, approximately how many hours does it take to fill the box?

(A) 2
(B) 8
(C) 16
(D) 24
(E) 48


Volume of rectangular box = 4*4*3 = 48 cubic feet.
2 cubic feet takes 1 hour
So, 48 cubic feet needs = 48/2 = 24 hours

Answer: D
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Re: Coins are dropped into a toll box so that the box is being [#permalink] New post   03 Jun 2023, 05:44
To find the number of hours it takes to fill the box, we can divide the volume of the box by the rate at which it is being filled.

The volume of the box is calculated by multiplying its length, width, and depth:

Volume = 4 feet * 4 feet * 3 feet = 48 cubic feet

Given that the box is being filled at a rate of approximately 2 cubic feet per hour, we can set up the following equation:

Time = Volume / Rate = 48 cubic feet / 2 cubic feet per hour = 24 hours

Therefore, it would take approximately 24 hours to fill the box, corresponding to option (D).
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Re: Coins are dropped into a toll box so that the box is being [#permalink]
03 Jun 2023, 05:44
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