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# combination problem

Author Message
Intern
Joined: 13 Jul 2003
Posts: 15

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29 Sep 2004, 10:37
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Hi,
Can someone help me with this question please.

Thanks

In a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 points each. A number of beads are then removed from the container. If the product of the point values of the removed beads is 147,000, how many red beads were removed?
Manager
Joined: 26 Sep 2004
Posts: 136

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29 Sep 2004, 10:56
caribcon wrote:
Hi,
Can someone help me with this question please.

Thanks

In a certain game, a large container is filled with red, yellow, green, and blue beads worth, respectively, 7, 5, 3, and 2 points each. A number of beads are then removed from the container. If the product of the point values of the removed beads is 147,000, how many red beads were removed?

147000 = (7^2)(3^1)(2^3)(5^3)
This means yu r drawing 2 red, 3 yellow,1 green, 3 blue beads.( Since 7,5,3,2 are all prime numbers the product is unique).
_________________

Franky
http://franky4gmat.blogspot.com

GMAT Club Legend
Joined: 07 Jul 2004
Posts: 5043
Location: Singapore

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30 Sep 2004, 00:22
Take the prime factorization of 147,000 = (147)*(1000)
= (21*7)*(10*100)
= (3*7*7)*(2*5*10*10)
= (3*7*7*2*5*2*5*2*5)
= (3)(7^2)(2^3)(5^3)

Red is worth 7 points, so two red beads are removed.
30 Sep 2004, 00:22
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