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# Computer and Printer---Prep Question

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Director
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18 Jul 2009, 10:29
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Computer and Printer---Prep Question

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Current Student
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Re: Computer and Printer---Prep Question [#permalink]

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18 Jul 2009, 11:13
Let the price of the basic computer be $$b$$
Let the price of the printer be $$p$$
given

$$b+p = 2500$$ ------ $$1$$

Now given

Enhanced computer is 500 more then basic computer
Let price of enhanced computer be $$e$$

$$\Rightarrow e = b+500$$ ---- $$2$$

Also given price of the printer is one fifth of the total price of the enhanced computer and the printer.

$$\Rightarrow p = \frac{1}{5} \times (e+p)$$

$$\Rightarrow p= \frac{1}{5} \times (b+500+p)$$

$$\Rightarrow 5p=b+500+p$$

$$\Rightarrow b-4p=(-500)$$ ---- $$3$$

Subtracting $$3$$from$$1$$ gives us

$$\Rightarrow 5p = 3000$$

$$\Rightarrow p=600$$

From 1

$$b+p=2500$$

$$b+600=2500$$

$$b=2500-600$$

$$b=1900$$

Current Student
Joined: 18 Jun 2009
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Re: Computer and Printer---Prep Question [#permalink]

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18 Jul 2009, 22:13
Variables

basic computer = bc
printer = p
enhanced computer = ec
First total = FT
Second total = ST

bc + p = 2500 ..... 1
FT = 2500

ec = bc + 500 .... 2

ec + p = 2500 + 500 (the question says enhanced computer is 500 more than the original computer)
therefore ec + p = 3000
ST = 3000

p = 1/5*ST = 600

ec = 3000 - p = 3000 - 600 = 2400

bc = ec - 500 = 2400 - 1000 = 1900

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Re: Computer and Printer---Prep Question [#permalink]

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28 Jul 2009, 13:22
B + P = 2500

E = B + 500

P = (B + 500)/4

B + (B + 500)/4 = 2500

(5/4)B +125 = 2500

(5/4)B = 2375

B = 1900

I think you are confusing the meaning of "1/5 of the total". It means that the printer is 1/5 of the Enhanced computer and printer combined, not the Enhanced computer alone. Therefore P = (B + 500)/4, NOT P = (B + 500)/5.
Re: Computer and Printer---Prep Question   [#permalink] 28 Jul 2009, 13:22
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