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Re: Consecutive perfect square [#permalink]
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gmatexam439 wrote:
DavidTutorexamPAL wrote:
gmatexam439 wrote:
Hi,

What does consecutive perfect square of prime numbers mean?

Is it: sq of 2,3 (square of only consecutive prime numbers)

OR

Is it: sq of 2,3 // sq of 3,5 // sq of 5,7 ...... and so on (consecutive perfect squares)

Please elaborate.

Regards


I haven't heard this expression before.. where is it from?

Your two options refer to different parsings of the phrase "consecutive perfect square of prime numbers"
Option 1 is the only ( (consecutive perfect square) of prime numbers)
Option 2 is any (consecutive (perfect square of prime numbers) ).

Without context I don't think you can separate the two.
(though personally, from a what-makes-more-sense-in-English point of view, I would go with option 2)


Hi DavidTutorexamPAL,

Please go through this question: https://gmatclub.com/forum/new-set-numb ... l#p1205358

The solution made me think the same way you did. I too am confused after having a look at the solution. Based on "what-makes-more-sense-in-English" i chose "E" as the answer while OA is "D". Hence my doubt.

Regards


That question does not say "consecutive perfect square of prime numbers" it says "consecutive perfect squares". Consecutive perfect square are 1 and 4, or 4 and 9...
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Consecutive perfect square [#permalink]
Bunuel wrote:
That question does not say "consecutive perfect square of prime numbers" it says "consecutive perfect squares". Consecutive perfect square are 1 and 4, or 4 and 9...


Hi Bunuel,

Question wrote:
If 0 < x < y and x and y are consecutive perfect squares, what is the remainder when y is divided by x?

(1) Both x and y is have 3 positive factors.
(2) Both √x and √y are prime numbers


From both the statements its clear that √x and √y are prime numbers. We are not given that √x and √y have to be consecutive; x and y should be consecutive.

So, \(2^2\)=4 & \(3^2\)=9; \(3^2\)=9 & \(5^2\)=25; \(5^2\)=25 & \(7^2\)=49 ...... and so on are all consecutive perfect squares that satisfy the information given in statement 1. Since we have more than 1 possible values, then how can we say that either statement 1 or statement 2 is sufficient?

Since, OA=D please explain where am I going wrong? I am unable to comprehend the OE.

Regards
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Consecutive perfect square [#permalink]
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gmatexam439 wrote:
Bunuel wrote:
That question does not say "consecutive perfect square of prime numbers" it says "consecutive perfect squares". Consecutive perfect square are 1 and 4, or 4 and 9...


Hi Bunuel,

Question wrote:
If 0 < x < y and x and y are consecutive perfect squares, what is the remainder when y is divided by x?

(1) Both x and y is have 3 positive factors.
(2) Both √x and √y are prime numbers


From both the statements its clear that √x and √y are prime numbers. We are not given that √x and √y have to be consecutive; x and y should be consecutive.

So, \(2^2\)=4 & \(3^2\)=9; \(3^2\)=9 & \(5^2\)=25; \(5^2\)=25 & \(7^2\)=49 ...... and so on are all consecutive perfect squares that satisfy the information given in statement 1. Since we have more than 1 possible values, then how can we say that either statement 1 or statement 2 is sufficient?

Since, OA=D please explain where am I going wrong? I am unable to comprehend the OE.

Regards


I think you missed the very first sentence of the solution provided: Notice that since x and y are consecutive perfect squares, then \(\sqrt{x}\) and \(\sqrt{y}\) are consecutive integers. The only primes, which are also consecutive integers are 2 and 3.
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Re: Consecutive perfect square [#permalink]
Bunuel wrote:
gmatexam439 wrote:
Bunuel wrote:
That question does not say "consecutive perfect square of prime numbers" it says "consecutive perfect squares". Consecutive perfect square are 1 and 4, or 4 and 9...


Hi Bunuel,

Question wrote:
If 0 < x < y and x and y are consecutive perfect squares, what is the remainder when y is divided by x?

(1) Both x and y is have 3 positive factors.
(2) Both √x and √y are prime numbers


From both the statements its clear that √x and √y are prime numbers. We are not given that √x and √y have to be consecutive; x and y should be consecutive.

So, \(2^2\)=4 & \(3^2\)=9; \(3^2\)=9 & \(5^2\)=25; \(5^2\)=25 & \(7^2\)=49 ...... and so on are all consecutive perfect squares that satisfy the information given in statement 1. Since we have more than 1 possible values, then how can we say that either statement 1 or statement 2 is sufficient?

Since, OA=D please explain where am I going wrong? I am unable to comprehend the OE.

Regards


I think you missed the very first sentence of the solution provided: Notice that since x and y are consecutive perfect squares, then \(\sqrt{x}\) and \(\sqrt{y}\) are consecutive integers. The only primes, which are also consecutive integers are 2 and 3.


Thank you Bunuel. I missed that part. It makes sense now.

Can you please share link for tricky PS/DS questions such as this one.

Regards
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Re: Consecutive perfect square [#permalink]
gmatexam439 wrote:
Thank you Bunuel. I missed that part. It makes sense now.

Can you please share link for tricky PS/DS questions such as this one.

Regards


Looks like I missed the boat :)
Anyways, glad you figured it out.
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Re: Consecutive perfect square [#permalink]
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