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# Consider three numbers a, b and c. Max (a,b,c) + Min (a,b,c) = 13.

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General GMAT Forum Moderator
Joined: 15 Jan 2018
Posts: 904
Concentration: General Management, Finance
GMAT 1: 720 Q50 V37
Consider three numbers a, b and c. Max (a,b,c) + Min (a,b,c) = 13.  [#permalink]

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07 Dec 2019, 22:58
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25% (medium)

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80% (02:26) correct 20% (02:39) wrong based on 46 sessions

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Consider three numbers a, b and c. Max (a,b,c) + Min (a,b,c) = 13. Median (a,b,c) - Mean (a,b,c) = 2. Find the median of a, b, and c.

A. 11.5
B. 9
C. 9.5
D. 12
E. 10

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Intern
Joined: 28 Sep 2019
Posts: 10
Location: India
GMAT 1: 610 Q49 V24
Consider three numbers a, b and c. Max (a,b,c) + Min (a,b,c) = 13.  [#permalink]

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07 Dec 2019, 23:08
Let's take a<b<c.
Max(a,b,c)+Min(a,b,c)=c+a+13
Median(a,b,c)-Mean(a,b,c)=b-(a+b+c)/3=2 => 2b-(a+c)=6 ; Substituting the value of a+c => 2b=19,hence b=9.5.

Ans C

Hope it's clear
SVP
Joined: 24 Nov 2016
Posts: 1545
Location: United States
Re: Consider three numbers a, b and c. Max (a,b,c) + Min (a,b,c) = 13.  [#permalink]

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22 Apr 2020, 07:14
DisciplinedPrep wrote:
Consider three numbers a, b and c. Max (a,b,c) + Min (a,b,c) = 13. Median (a,b,c) - Mean (a,b,c) = 2. Find the median of a, b, and c.

A. 11.5
B. 9
C. 9.5
D. 12
E. 10

if median-mean>0, then median>mean
if med>mean, then median cannot be the max or min
assume that a=max, b=med, c=min
a+c=13 and b-a+b+c/3=2
b-(b+13)/3=2, 3b-b+13=6,
2b=19, b=9.5=median

Ans (C)
Re: Consider three numbers a, b and c. Max (a,b,c) + Min (a,b,c) = 13.   [#permalink] 22 Apr 2020, 07:14

# Consider three numbers a, b and c. Max (a,b,c) + Min (a,b,c) = 13.

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