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Could someone provide a solution to this GMATPrep IR Questio

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Intern
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Could someone provide a solution to this GMATPrep IR Questio [#permalink]

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25 Oct 2012, 08:24
Hi Guys,

PFA the GMAT PREP IR Question as a pic file. Could someone please provide a solution to this GMATPrep IR Question?

Thanks,
harikris
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Intern
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Re: Could someone provide a solution to this GMATPrep IR Questio [#permalink]

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30 Oct 2012, 18:15
2pi R = 5.50

Therefore, R = 5.50/2*7/22 = 0.875 Find R^2 = 0.7656

So, Surface area = 4 PI R^2 = 9.625 Sq M.

Cost of finishing a sphere = 92* 4 PI R^2 = 92 * 9.625 = 885 So Approx. $900 Find the same way for other circumference of 7.85M SVP Joined: 14 Apr 2009 Posts: 2069 Location: New York, NY Followers: 394 Kudos [?]: 1441 [0], given: 8 Re: Could someone provide a solution to this GMATPrep IR Questio [#permalink] Show Tags 06 Nov 2012, 14:16 On the Integrated Reasoning section, you have access to a calculator. So just solve the formula for radius of the sphere first. If you know circumference as 5.50 meters, then pi * d = 5.50 d = 5.50 / 3.14 d = 1.75 Since radius is half the diameter, radius is 0.876. Now we have to solve for surface area then multiply by cost / square meter. Surface area is 4pi*r^2 4 * 3.14 * 0.876 * 0.876 = 9.636$92 / square meter

OK so $92 / sq meter * 9.636 square meters =$886.5

After some rounding that is \$900 so that is the best answer for the first column.
Re: Could someone provide a solution to this GMATPrep IR Questio   [#permalink] 06 Nov 2012, 14:16
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