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my answer is 56, although i am not happy about how i came to it..
#of 1 digit numbers: 1 For 2 digits we have (2,3),(4,1) #of 2 digit numbers: 4 + 1 (this one is derived from adding a 0 to the 1 digit number) = 5 For 3 digits we have (1,1,3)(1,2,2) #of 3 digit numbers: 3!/2!+3!/2!+ 1 (500) + 4*2 (adding one zero to the 2 digit numbers - 2 ways, in between or at the end) = 15 For 4 digits we have (1,1,1,2) #of 4 digit numbers: 4!/3! + 1 (5000) + 4*3 (adding 2 zeroes to the 2 digit numbers - 3 ways, in between, at the end, or one in between and one at the end) + 6*3 (adding one 0 to the 3 digit numbers - 3 ways, after 1st digit, after 2nd digit, after 3rd digit) = 35
I got this one also after like 6 minutes. My response would simply be this... if you were to see something this difficult on the test... just take a wild guess since you already are in the 99% rofl
Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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