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# Crack the GMAT question on PS:

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Manager
Joined: 11 Apr 2009
Posts: 163
Followers: 2

Kudos [?]: 101 [0], given: 5

Crack the GMAT question on PS: [#permalink]

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07 May 2009, 15:22
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Question Stats:

0% (00:00) correct 100% (01:59) wrong based on 0 sessions

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AB + CD = AAA, where AB and CD are two-digit numbers and AAA is a three digit number; A, B, C, and D are distinct positive integers. In the addition problem above, what is the value of C?

(A) 1

(B) 3

(C) 7

(D) 9

(E) Cannot be determined

Is there a quick way of figuring out the above?
Intern
Joined: 02 Feb 2009
Posts: 36
Followers: 0

Kudos [?]: 5 [0], given: 2

Re: Crack the GMAT question on PS: [#permalink]

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07 May 2009, 16:23
my thoughts are AB + CD can at most be 99 + 99 which is less than 222, 333, 444 etc, therfore AAA must be 111.

Then test out a couple of possibilities. Since we figured out that A is 1, then limiting numbers are 10 and 19
10 and 11 dont work since you need a 3 digit number to sum to 111. therefore new limits are 12 and 19.

it could be 19 + 92 or it could be 12 + 99, 11 etc. Both cases c = 9

answer is D in my opinion. I cant see any way of doing this kind of problem more quickly. I think you just have to think through the problem logically.

gmatprep09 wrote:
AB + CD = AAA, where AB and CD are two-digit numbers and AAA is a three digit number; A, B, C, and D are distinct positive integers. In the addition problem above, what is the value of C?

(A) 1

(B) 3

(C) 7

(D) 9

(E) Cannot be determined

Is there a quick way of figuring out the above?
Manager
Joined: 11 Apr 2009
Posts: 163
Followers: 2

Kudos [?]: 101 [0], given: 5

Re: Crack the GMAT question on PS: [#permalink]

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07 May 2009, 19:29
Yes it is. Thanks
Re: Crack the GMAT question on PS:   [#permalink] 07 May 2009, 19:29
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