Cyclist M leaves point P at 12 noon and travels in a straight path at

Distance to be covered by M till 4 PM = 80 Miles

Now, P covers 80 miles starting at 2 PM and Completing it at 4 PM , so P travels 80 Miles in 2 Hours

Thus, Average distance traveled by P is 40 Miles/Hour, Answer must be (E)

There are two cyclists traveling along the same path.
One of them lets say cyclist A has a speed of 20 miles per hr and starts traveling at 12 PM
Another cyclist let us say B has a speed that we do not know and that is what is required by the question.
Cyclist B starts traveling along the same path as A but 2 hrs later than A i.e. at 2PM

Also at 4PM both cyclists travel the same distance from the starting point P.

Let us find out how much can cyclist A travel in 4 hrs, that would be 20∗4=8020∗4=80 miles
Since cyclist B started at 2PM and reached the exact distance as cyclist A at 4PM. Cyclist B traveled for 2 hrs only.
Therefore if Cyclist B speed was x miles per hr then 2x = 80
or, x=40x=40 which is the speed of cyclist B

So answer is E

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