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cylindrical container volume

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Intern
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Joined: 17 Apr 2010
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cylindrical container volume [#permalink]

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New post 20 Apr 2010, 00:29
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A cylindrical container, used for holding oil, had a diameter of 16 m and a height of 3 m. To increase the volume, such that if X m are added to either the radius or the height, the increase in volume is the same. Thus, X will be

A. 16 m
B. 5.33 m
C. 6.77 m
D. 3.56 m
E. 4 m

OA will follow..
Intern
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Joined: 19 Apr 2010
Posts: 4
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Kudos [?]: 0 [0], given: 2

Re: cylindrical container volume [#permalink]

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New post 20 Apr 2010, 00:39
gmatstar10 wrote:
A cylindrical container, used for holding oil, had a diameter of 16 m and a height of 3 m. To increase the volume, such that if X m are added to either the radius or the height, the increase in volume is the same. Thus, X will be

A. 16 m
B. 5.33 m
C. 6.77 m
D. 3.56 m
E. 4 m

OA will follow..


Volume = pi *R^2* H
New volume = pi *8^2* (3 + X) =pi* (8 + X)^2 *3
X = 16/3 m = 5.33 m.
what's OA ?
Intern
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Re: cylindrical container volume [#permalink]

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New post 21 Apr 2010, 22:01
gmatstar10 wrote:
A cylindrical container, used for holding oil, had a diameter of 16 m and a height of 3 m. To increase the volume, such that if X m are added to either the radius or the height, the increase in volume is the same. Thus, X will be

A. 16 m
B. 5.33 m
C. 6.77 m
D. 3.56 m
E. 4 m

OA will follow..

hi,
diameter = 16 hence radius is 8
as the increase in volume is same,
\(\pi r^2 h_1 = \pi r_1^2 h\)
\(8^2 (3+x) = (8+x)^2 3\)
\(64(3+x) = 3(x^2+16x+64)\)
\(64x = 3x^2 + 48x\)
\(x = \frac {16}{3}\)
_________________

CHEERS
fivezero7

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Re: cylindrical container volume [#permalink]

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New post 22 Apr 2010, 02:05
thanks guys, OA
[Reveal] Spoiler:
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Re: cylindrical container volume   [#permalink] 22 Apr 2010, 02:05
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