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# D01-10

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Intern
Joined: 18 Jun 2017
Posts: 13

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14 Feb 2018, 23:57
can we take x not equal to zero for granted in such questions? If yes, then here is the simple way of solving it

1/x >-1; x>-1 {A alone is not sufficient}
1/x^5 >1/x^3; X^3 > X^5 which is possible only is X<1. { so B alone is sufficient ..Simple}
Intern
Joined: 08 Aug 2017
Posts: 20
GMAT 1: 690 Q49 V35

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04 Mar 2018, 12:56
Hi Bunuel

I have a doubt in Statement 1 for the case x<0.

I got this,
for x<0, 1/(-x)>-1, so when we multiply by -1 and flip signs,we get 1/x<1, so x>1.

Can you please explain how you got 1+x<0 for x<0.
Please correct me. I am doing something wrong here. Is there any concept file to know more about inequalities? I was not able to find any chapter in GMATClub Maths book.
Math Expert
Joined: 02 Sep 2009
Posts: 47015

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04 Mar 2018, 13:13
1
pantera07 wrote:
Hi Bunuel

I have a doubt in Statement 1 for the case x<0.

I got this,
for x<0, 1/(-x)>-1, so when we multiply by -1 and flip signs,we get 1/x<1, so x>1.

Can you please explain how you got 1+x<0 for x<0.
Please correct me. I am doing something wrong here. Is there any concept file to know more about inequalities? I was not able to find any chapter in GMATClub Maths book.

If x is negative, then x denotes negative quantity, no need to replace x with -x.

9. Inequalities

For more check Ultimate GMAT Quantitative Megathread

Hope it helps.
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Status: EAT SLEEP GMAT REPEAT!
Joined: 28 Sep 2016
Posts: 178
Location: India

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30 May 2018, 10:32
What sort of values shall we use in such type of questions?

Can you suggest Bunuel

Bunuel wrote:
Is $$x$$ greater than 1?

(1) $$\frac{1}{x} \gt -1$$

(2) $$\frac{1}{x^5} \gt \frac{1}{x^3}$$

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Regards,

Re: D01-10   [#permalink] 30 May 2018, 10:32

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# D01-10

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