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# D01-12

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Intern
Joined: 04 Dec 2017
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09 Feb 2019, 22:48
I think this is a high-quality question and I agree with explanation.
VP
Joined: 09 Mar 2018
Posts: 1001
Location: India

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09 Feb 2019, 23:28
Bunuel wrote:
If $$N = 1234@$$ and $$@$$ represents the units digit of $$N$$, is $$N$$ a multiple of 5?

(1) $$@!$$ is not divisible by 5

(2) $$@$$ is divisible by 9

Lets do 3 things first

For N to be divisible by 5 @ has to be 0 or 5

Second 0! = 1

Third: zero is a multiple of every integer (except zero itself)

(1) $$@!$$ is not divisible by 5
@!, 0! = 1, when put back in the question, this will make N divisible by 5,, Yes
4! =24,when put back in the question, this will make N divisible by 5, No

(2) $$@$$ is divisible by 9[/quote]
m can be 0, this is / by 9, when put back in the question, this will make N divisible by 5, Yes
m can be 9, when put back in the question, this will make N divisible by 5,No

We have the common value from both the statements
0, making N divisible by 5

C
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Re: D01-12   [#permalink] 09 Feb 2019, 23:28

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# D01-12

Moderators: chetan2u, Bunuel

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