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D01-33

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Manager
Joined: 10 Feb 2017
Posts: 51
Location: India
GMAT 1: 680 Q50 V30
GPA: 3.9

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20 Mar 2017, 22:54
as per question the diameter of inscribed circle should be pi not of semi circle.
the first line of the question clearly talks about the inscibed circle where it is given 'it is inscibed in a semi circle with diameter pi and is shown below'.

i think question fails to clear this out and hence the answer can vary.
Math Expert
Joined: 02 Sep 2009
Posts: 45219

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21 Mar 2017, 04:21
smanujahrc wrote:
as per question the diameter of inscribed circle should be pi not of semi circle.
the first line of the question clearly talks about the inscibed circle where it is given 'it is inscibed in a semi circle with diameter pi and is shown below'.

i think question fails to clear this out and hence the answer can vary.

I think it's clear from the stem that $$\pi$$ is diameter of semicircle.
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Manager
Joined: 01 Nov 2016
Posts: 69
Concentration: Technology, Operations

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15 Apr 2017, 14:47
Bunuel wrote:
Since the radius of the big circle ($$\frac{\pi}{2}$$) is twice the radius of the inscribed circle ($$\frac{\pi}{4}$$) then its area is 4 times greater than the area of the inscribed circle (because in the area formula the radius is squared.

Bunuel wrote:
Thus the area of the semicircle is $$\frac{4}{2}=2$$ times greater than the area of the inscribed circle

Took me a while but I finally understand this. I originally solved this algebraically but that takes too long. It's better to use the area ratio information.

(Radius Big Circle/ Radius Inner Circle) = (pi/2) / (pi/4) = 2/1

(Area Big Circle/ Area Inner Circle) = (2/1)^2 = 4/1

(Area Semicircle / Area Inner Circle) = 4/1 * 1/2 = 2/1 <-- answer
Intern
Joined: 26 Dec 2014
Posts: 9

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24 Aug 2017, 05:49
Which circle's diameter is pi? It is confusing and not even shown in the figure.
Manager
Joined: 03 Jun 2017
Posts: 50
Location: United Kingdom
GMAT 1: 610 Q47 V27
GMAT 2: 700 Q49 V34
GPA: 4

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29 Dec 2017, 07:44
I think this is a high-quality question and I agree with explanation.
Intern
Joined: 17 Jun 2017
Posts: 1

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05 Jan 2018, 01:43
Ansari1 wrote:

Then area of semicircle is pi cube/8. And area of circle is pi cube/32.

The question is ratio between area of semicircle to area not covered by circle.

Area not covered is pi cube/8 minus pi cube/32.

That is 3 pi cube/32.

Atlast, ratio = (pi cube/8) / (3 pi cube/32)
= 4/3

Then answer should be 4:3 !?

Whether my approach to this is wrong? Correct me, if is it so..
Ansari1 wrote:

Then area of semicircle is pi cube/8. And area of circle is pi cube/32.

The question is ratio between area of semicircle to area not covered by circle.

Area not covered is pi cube/8 minus pi cube/32.

That is 3 pi cube/32.

Atlast, ratio = (pi cube/8) / (3 pi cube/32)
= 4/3

Then answer should be 4:3 !?

Whether my approach to this is wrong? Correct me, if is it so..
Actually even I tried the same method to get to the answer as 4:3 but whats wrong with my assumption is ..I multiplied the area of the semi-circle into 2 .. which shouldn't be the case when we are working only with the area of the circle ..
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Joined: 13 Apr 2018
Posts: 1

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14 Apr 2018, 23:17
pi3/4/3pi3/16 = 4:3
Re: D01-33   [#permalink] 14 Apr 2018, 23:17

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