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D01-42

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Senior Manager
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New post 22 Dec 2014, 08:10
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If x is an integer and \(9 \lt x^2 \lt 99\), then what is the value of maximum possible value of \(x\) minus minimum possible value of \(x\)?

A. \(5\)
B. \(6\)
C. \(7\)
D. \(18\)
E. \(20\)
Senior Manager
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Status: Some status
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GMAT 4: 660 Q51 V49
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New post 22 Dec 2014, 08:10
Official Solution:

If x is an integer and \(9 \lt x^2 \lt 99\), then what is the value of maximum possible value of \(x\) minus minimum possible value of \(x\)?

A. \(5\)
B. \(6\)
C. \(7\)
D. \(18\)
E. \(20\)


Notice that \(x\) can take positive, as well as negative values to satisfy \(9 \lt x^2 \lt 99\), hence \(x\) can be: -9, -8, -7, -6, -4, 4, 5, 6, 7, 8, or 9. We are asked to find the value of x(max)-x(min), and since x(max)=9 and x(min)=-9 then x(max)-x(min)=9-(-9)=18.


Answer: D
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New post 21 Feb 2017, 19:43
mpmbtr wrote:
Official Solution:

If x is an integer and \(9 \lt x^2 \lt 99\), then what is the value of maximum possible value of \(x\) minus minimum possible value of \(x\)?

A. \(5\)
B. \(6\)
C. \(7\)
D. \(18\)
E. \(20\)

Notice that \(x\) can take positive, as well as negative values to satisfy \(9 \lt x^2 \lt 99\), hence \(x\) can be: -9, -8, -7, -6, -4, 4, 5, 6, 7, 8, or 9.
We are asked to find the value of \(x(max)-x(min)\), and since \(x(max)=9\) and \(x(min)=-9\) then \(x(max)-x(min)=9-(-9)=18\).

Answer: D


Dear Bunuel, Shall we consider x instead of \(x^2\) in the official solution?

\(9<x^2<99\)

\(\sqrt{9}<x<\sqrt{99}\)

\(\sqrt{9}<x<\sqrt{100}\)

\(3<x<10\)

\(-3<x<-10\)
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D01-42   [#permalink] 21 Feb 2017, 19:43
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