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# Derrick and Lena a married couple attending the same

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Intern
Joined: 29 Aug 2012
Posts: 26

Kudos [?]: 36 [0], given: 56

Schools: Babson '14
GMAT Date: 02-28-2013
Derrick and Lena a married couple attending the same [#permalink]

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28 Nov 2012, 10:11
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Derrick and Lena a married couple attending the same business school, go to a corporate presentation that ends with two sequential drawings of PDA, among the 60 attending students. If each attendant is given one ticket participating in the lottery of the two PDA's and if each winning ticket is removed from the urn, what is the probability that both PDA will go to the couple?

[Reveal] Spoiler:
Answer to this question is : 1/1770

Kudos [?]: 36 [0], given: 56

Math Expert
Joined: 02 Sep 2009
Posts: 42618

Kudos [?]: 135758 [1], given: 12708

Re: Derrick and Lena a married couple attending the same [#permalink]

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29 Nov 2012, 02:42
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Expert's post
himanshuhpr wrote:
Derrick and Lena a married couple attending the same business school, go to a corporate presentation that ends with two sequential drawings of PDA, among the 60 attending students. If each attendant is given one ticket participating in the lottery of the two PDA's and if each winning ticket is removed from the urn, what is the probability that both PDA will go to the couple?

[Reveal] Spoiler:
Answer to this question is : 1/1770

The first PDA goes to Derek and the second to Lena - 1/60*1/59;
The first PDA goes to Lena and the second to Derek - 1/60*1/59;

Thus, the overall probability that both PDA will go to the couple is 2*1/60*1/59=1/1770.

Hope it's clear.
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Kudos [?]: 135758 [1], given: 12708

Intern
Joined: 29 Aug 2012
Posts: 26

Kudos [?]: 36 [0], given: 56

Schools: Babson '14
GMAT Date: 02-28-2013
Re: Derrick and Lena a married couple attending the same [#permalink]

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29 Nov 2012, 06:48
Bunuel wrote:

The first PDA goes to Derek and the second to Lena - 1/60*1/59;
The first PDA goes to Lena and the second to Derek - 1/60*1/59;

Thus, the overall probability that both PDA will go to the couple is 2*1/60*1/59=1/1770.

Hope it's clear.

Just for understanding it better, is it right to think in following way:

In 1st case , till the time Derek receives the first PDA every of the 60 participants including Lena have the equal probability of 1/60 of receiving the 1st PDA and after its confirmed that Derek does receive the 1st PDA, the remaining all participants including Lena will have 1/59 probability of receiving the 2nd PDA.

^^^ thinking above on the lines of 'row' concept.

Kudos [?]: 36 [0], given: 56

Intern
Joined: 21 Oct 2012
Posts: 25

Kudos [?]: 13 [0], given: 15

GMAT Date: 01-19-2013
Re: Derrick and Lena a married couple attending the same [#permalink]

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06 Dec 2012, 12:57
The probability of picking up first ticket is 2/60, second is 1/59.
Combined is 2/3540, which is equal to 1/1770
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Kudos [?]: 13 [0], given: 15

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Re: Derrick and Lena a married couple attending the same [#permalink]

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08 Jan 2017, 14:31
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Re: Derrick and Lena a married couple attending the same   [#permalink] 08 Jan 2017, 14:31
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