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# diagnostic test

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Manager
Joined: 21 Feb 2010
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13 Jun 2010, 19:37
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this question is from OG diagnostic test. the question itself is easy, but the wording is confusing...
question: a closed cylindrical tank contains 36π cubic feet of water and is filled to half its capacity. when the tank is placed upright on its circular base on level ground, the height of the water in the tank is 4 feet. when the tank is placed on its side on level ground, what is the height, in feet, of the surface of the water above the ground?
this is my answer: since the tank is filled with half of its capacity which is 18π and the height is 4 feet, π(r^2)4 =18π we get r=(3\sqrt{2}) / 2
then when the tank is placed on its side, the height of the water should be equal to its radius r since the tank is half of its capacity.
but the answer is 3. can someone explain to me please? thanks!

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Manager
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13 Jun 2010, 20:59
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Try plugging in the numbers in the formula:

pi*(r^2) * h = 36*2 = 72
since height of water = 4, the height of the cylinder = 8 ==> r = 3;
When the cylinder is placed sideways, it fills to half the height, in this case, the height is nothing but the radius, which is 3..

hope this helps...b
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Manager
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14 Jun 2010, 08:55
thanks!

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Re: diagnostic test   [#permalink] 14 Jun 2010, 08:55
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# diagnostic test

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