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# Diagonals of rectangle ABCD ( AB > BC ) cross at point E.

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CEO
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Diagonals of rectangle ABCD ( AB > BC ) cross at point E. [#permalink]

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22 Oct 2007, 08:08
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Diagonals of rectangle ABCD (AB > BC) cross at point E. What is the value of AEB?

1. EDC is 15 degrees
2. ACB is 75 degrees

Side note: What is the point of telling us that AB > BC?
Manager
Joined: 18 Jun 2007
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22 Oct 2007, 08:26
D as well. When drawing the rectangle it was helpful to know that ab > bc...on second thought, it wasn't helpful, but it made it easier to draw the rectangle the way they wanted it.

i wish i could elaborate on the answer but its hard to show geometry with just text.
CEO
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Location: New York City
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22 Oct 2007, 13:48
What is the concept being tested? Can someone explain the answer step by step. thanks
Intern
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22 Oct 2007, 14:08
Just the concept of triangles is being tested here. Also the fact that the rectangle has rt angles @ 4 corners
Hence if u get one angle u can derive all the other angles and sum of all angles of a triangle is 180 hence u can find the reminaing angles.

Darshan
bmwhype2 wrote:
What is the concept being tested? Can someone explain the answer step by step. thanks
22 Oct 2007, 14:08
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# Diagonals of rectangle ABCD ( AB > BC ) cross at point E.

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