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Did one of the 3 members of a certain team sell at least 2

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Did one of the 3 members of a certain team sell at least 2 [#permalink]

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Did one of the 3 members of a certain team sell at least 2 raffle tickets yesterday?

(1) The 3 members sold a total of 6 raffle tickets yesterday.
(2) No 2 of the members sold the same number of raffle tickets yesterday.

[Reveal] Spoiler:
Acc to (1) one should mean only 1 member sold atleast 2 raffle, NOT atleast one member sold atleast 2 raffle.
Hence, the two contradictory options should be :
0,0,6- one member sold atleast 2 raffle
2,2,2- more than one member sold atleast 2 raffle.

Please explain why should D be the answer. This is a Q from GMAT Prep with D as answer, please take notice.
[Reveal] Spoiler: OA

Last edited by hazelnut on 25 Jun 2017, 05:59, edited 3 times in total.
EDITED THE QUESTION.

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Re: Did one of the 3 members of a certain team sell at least 2 [#permalink]

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Did one of the 3 members of a certain team sell at least 2 raffle tickets yesterday?

The question basically asks whether there is a member who sold at least 2 tickets (so 2 or more).

(1) The 3 members sold a total of 6 raffle tickets yesterday. If each of the 3 members sold less than 2 tickets, then the total # of tickets sold cannot be 6, hence at least one member sold at least 2 tickets. Sufficient.

Or: can we split 6 tickets so that ALL 3 members to have sold less than 2 tickets? No: (6,0,0); (5,1,0), (4,1,1); (4,2,0); (3,3,0),(3,2,1), (2,2,2). Sufficient.

(2) No 2 of the members sold the same number of raffle tickets yesterday. If one member sold 0 tickets and another sold 1 ticket (the least possible numbers), then the third one must have sold more than 1, so 2 or more. Sufficient.

Answer: D.

Hope it's clear.
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Re: Did one of the 3 members of a certain team sell at least 2 [#permalink]

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New post 04 Aug 2012, 10:50
Bunuel wrote:
Did one of the 3 members of a certain team sell at least 2 raffle tickets yesterday?

The question basically asks whether there is a member who sold at least 2 tickets (so 2 or more).

(1) The 3 members sold a total of 6 raffle tickets yesterday. If each of the 3 members sold less than 2 tickets, then the total # of tickets sold cannot be 6, hence at least one member sold at least 2 tickets. Sufficient.

Or: can we split 6 tickets so that ALL 3 members to have sold less than 2 tickets? No: (6,0,0); (5,1,0), (4,1,1); (4,2,0); (3,3,0),(3,2,1), (2,2,2). Sufficient.

(2) No 2 of the members sold the same number of raffle tickets yesterday. If one member sold 0 tickets and another sold 1 ticket (the least possible numbers), then the third one must have sold more than 1, so 2 or more. Sufficient.

Answer: D.

Hope it's clear.


If the Q asks "whether there is a member who sold at least 2 tickets (so 2 or more)" then it should have been framed as atleast one NOT one which indicates Exactly one. Hence the doubt. Infact, i would say the Q should use the word Atleast or Exactly to make it clear.

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Re: Did one of the 3 members of a certain team sell at least 2 [#permalink]

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New post 04 Aug 2012, 12:44
saurabhkhatrinitk wrote:
Bunuel wrote:
Did one of the 3 members of a certain team sell at least 2 raffle tickets yesterday?

The question basically asks whether there is a member who sold at least 2 tickets (so 2 or more).

(1) The 3 members sold a total of 6 raffle tickets yesterday. If each of the 3 members sold less than 2 tickets, then the total # of tickets sold cannot be 6, hence at least one member sold at least 2 tickets. Sufficient.

Or: can we split 6 tickets so that ALL 3 members to have sold less than 2 tickets? No: (6,0,0); (5,1,0), (4,1,1); (4,2,0); (3,3,0),(3,2,1), (2,2,2). Sufficient.

(2) No 2 of the members sold the same number of raffle tickets yesterday. If one member sold 0 tickets and another sold 1 ticket (the least possible numbers), then the third one must have sold more than 1, so 2 or more. Sufficient.

Answer: D.

Hope it's clear.


If the Q asks "whether there is a member who sold at least 2 tickets (so 2 or more)" then it should have been framed as atleast one NOT one which indicates Exactly one. Hence the doubt. Infact, i would say the Q should use the word Atleast or Exactly to make it clear.


Not so (even though I do see why you are confused).

Actually it's opposite, if the question meant exactly (only) one, then it would say so.
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Re: Did one of the 3 members of a certain team sell at least 2 [#permalink]

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Re: Did one of the 3 members of a certain team sell at least 2 [#permalink]

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Re: Did one of the 3 members of a certain team sell at least 2 [#permalink]

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Re: Did one of the 3 members of a certain team sell at least 2 [#permalink]

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New post 29 Nov 2016, 20:45
The question looks kind of tricky to me,
However deep diving I think- the bottomline of the question is did any of the 3 members sold more than 1 ticket.

Now total no of tickets sold in 6 and tickets cannot be negative or fractions hence yes statement 1 is true.

Similarly statement 2 is also true if 3 of them sold different number of tickets then they can sell (0,1, 2) tickets .

Thus both the statements are sufficient to prove it correct.

Hope this helps.

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Re: Did one of the 3 members of a certain team sell at least 2 [#permalink]

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New post 02 Feb 2017, 18:35
statement (1):
there's a statement called the pigeonhole principle, which basically says the following two things:
* if the AVERAGE of a set of integers is an INTEGER n, then at least one element of the set is > n.
* if the AVERAGE of a set of integers is a NON-INTEGER n, then at least one element of the set is > the next integer above n.
this principle is easy to prove: if you assume the contrary, then you get the absurd situation in which every element of a set is below the average of the set. that is of course impossible.

specifically, statement (1) is a case of the first part of the principle: the average of the set is 6/3 = 2, so at least one element of the set must be 2 or more.


statement (2):
there are only two ways not to sell at least 2 tickets: sell 0 tickets, and sell 1 ticket.
if everyone sells a different # of tickets, then you can't fit three people into these two categories.
therefore, someone must have sold at least 2 tickets.

Hence D.
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Re: Did one of the 3 members of a certain team sell at least 2 [#permalink]

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Did one of the 3 members of a certain team sell at least 2 raffle tickets yesterday.

(1) The 3 members sold a total of 6 raffle tickets yesterday

(2) No 2 of the members sold the same number of raffle tickets yesterday

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Re: Did one of the 3 members of a certain team sell at least 2 [#permalink]

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New post 10 Feb 2017, 23:33
ram186 wrote:
Did one of the 3 members of a certain team sell at least 2 raffle tickets yesterday.

(1) The 3 members sold a total of 6 raffle tickets yesterday

(2) No 2 of the members sold the same number of raffle tickets yesterday


(1) 3 members sold a total of 6 raffle tickets - Combinations are 2,2,2, 4,1,1, 5,0,1, and so on. So in each case at least one would've sold more than 2. - Sufficient

(2) No 2 of the members sold the same number of raffle tickets yesterday - We don't know how many tickets were sold yesterday but we know no 2 person sold the same no. of tickets. Since they are tickets they must be 3 different non negative integers. The 2 different smallest non negative integers are 0, and 1. Hence the other one has to be either 2 or greater than 2. So either way we can tell one person has sold at least 2 raffle tickets. - Sufficient

Hope this explains.

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Re: Did one of the 3 members of a certain team sell at least 2 [#permalink]

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New post 11 Feb 2017, 11:54
Sure. This is a good alternative solution.

But will you really remember this principle on the test day ?

In my opinion, it's better to go intuitive about questions. But that's what I think. Everyone's got his/her way of doing things !

anairamitch1804 wrote:
statement (1):
there's a statement called the pigeonhole principle, which basically says the following two things:
* if the AVERAGE of a set of integers is an INTEGER n, then at least one element of the set is > n.
* if the AVERAGE of a set of integers is a NON-INTEGER n, then at least one element of the set is > the next integer above n.
this principle is easy to prove: if you assume the contrary, then you get the absurd situation in which every element of a set is below the average of the set. that is of course impossible.

specifically, statement (1) is a case of the first part of the principle: the average of the set is 6/3 = 2, so at least one element of the set must be 2 or more.


statement (2):
there are only two ways not to sell at least 2 tickets: sell 0 tickets, and sell 1 ticket.
if everyone sells a different # of tickets, then you can't fit three people into these two categories.
therefore, someone must have sold at least 2 tickets.

Hence D.

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Did one of the 3 members of a certain team sell at least 2 [#permalink]

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New post 16 Aug 2017, 03:02
I agree with some people who posted their doubts about the questions earlier. I chose option E.

If the question had clearly mentioned "Did atleast one of the 3 members of a certain team sell at least 2 raffle tickets yesterday." then it would've caused much less confusion.

But at the end of the day it's an official question, so we can't argue much. :-/

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Did one of the 3 members of a certain team sell at least 2   [#permalink] 16 Aug 2017, 03:02
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