Difficult one: Tourist ourchased ticket : Quant Question Archive [LOCKED]
Check GMAT Club Decision Tracker for the Latest School Decision Releases https://gmatclub.com/AppTrack

 It is currently 21 Feb 2017, 00:48

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Difficult one: Tourist ourchased ticket

Author Message
Manager
Joined: 05 Nov 2005
Posts: 232
Location: Germany
Followers: 2

Kudos [?]: 70 [0], given: 0

Difficult one: Tourist ourchased ticket [#permalink]

### Show Tags

03 Dec 2005, 08:43
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Please help, I have tried over half an hour to solve that problem, but I just can*t get it right. Can someone please explain it?

A tourist purchased a total of $1500 worth of traveler's check's in$10 and $50 denominations. During the trip the tourist cashed 7 checks and then lost all of the rest. If the number of$10 checks cashed was one
more or one less than the number of
$50 checks cashed, what is the minimum possible value of the checks that were lost? A 1430 B 1310 C 1290 D 1270 E 1150 Intern Joined: 05 Nov 2005 Posts: 33 Location: London Followers: 0 Kudos [?]: 1 [0], given: 0 Re: Difficult one: Tourist ourchased ticket [#permalink] ### Show Tags 03 Dec 2005, 10:06 sandalphon wrote: Please help, I have tried over half an hour to solve that problem, but I just can*t get it right. Can someone please explain it? A tourist purchased a total of$1500 worth of traveler's
check's in $10 and$50 denominations. During the trip
the tourist cashed 7 checks and then lost all
of the rest. If the number of $10 checks cashed was one more or one less than the number of$50 checks cashed, what is the minimum possible value of
the checks that were lost?

A 1430
B 1310
C 1290
D 1270
E 1150

I pick D, since if there is a total of 7 cashed checks, with the relationship of x+1 or x-1, its 4:3. If we want the minimum lost, then we want the maximum cashed in, so take 4:3 as the ratio of 4 $50 and 3:$10, totalling a maximum cashed in amount of $230, minimising our lost to 1500-230=1270 I hope there is no flaw in the logic. Current Student Joined: 23 Oct 2005 Posts: 243 Schools: Cranfield SOM Followers: 2 Kudos [?]: 13 [0], given: 2 Re: Difficult one: Tourist ourchased ticket [#permalink] ### Show Tags 04 Dec 2005, 09:13 wlee76 wrote: sandalphon wrote: Please help, I have tried over half an hour to solve that problem, but I just can*t get it right. Can someone please explain it? A tourist purchased a total of$1500 worth of traveler's
check's in $10 and$50 denominations. During the trip
the tourist cashed 7 checks and then lost all
of the rest. If the number of $10 checks cashed was one more or one less than the number of$50 checks cashed, what is the minimum possible value of
the checks that were lost?

A 1430
B 1310
C 1290
D 1270
E 1150

I pick D, since if there is a total of 7 cashed checks, with the relationship of x+1 or x-1, its 4:3. If we want the minimum lost, then we want the maximum cashed in, so take 4:3 as the ratio of 4 $50 and 3:$10, totalling a maximum cashed in amount of $230, minimising our lost to 1500-230=1270 I hope there is no flaw in the logic. I think I saw this Q recently in a princeton review online test. If I remember right the OA and OE are as you have given. SVP Joined: 16 Oct 2003 Posts: 1810 Followers: 5 Kudos [?]: 139 [0], given: 0 ### Show Tags 04 Dec 2005, 18:37 To make the value of lost to minimum we should have maximum number of$50 checks encashed

4*$50 = 200 + 3*$`0 = 30 = 230 so subtract this from 1500 we get 1270

if you use 4 $10 checks then the values are 190 and we get 1310. Manager Joined: 20 Nov 2005 Posts: 54 Location: Indianapolis, IN Followers: 1 Kudos [?]: 13 [0], given: 0 ### Show Tags 05 Dec 2005, 12:20 I did it as follows: x = number of$10 checks
y = number of $50 checks According to the statements in the problem, x=y+1 or x=y-1, and x+y = 7 substitute x+y=7 into x=y+1 to get: x=7-x+1 ---> 2x=8, x=4 If we had 4$10 checks that means we had 3 50 checks. For a total amount cashed of $190. 1500-190 cashed =$310

BUT, since we need to MINIMIZE the amount LOST (not the amount cashed), then we need to maximize the amount CASHED, which would mean we need to substitute x+y=7 into x=y-1...

doing that you get
x=7-x-1
2x=6
x=3

which means the traveler cashed $230, and lost at the most, 1500-230=$1270.

Senior Manager
Joined: 14 Apr 2005
Posts: 417
Location: India, Chennai
Followers: 2

Kudos [?]: 16 [0], given: 0

Re: Difficult one: Tourist ourchased ticket [#permalink]

### Show Tags

06 Dec 2005, 00:38
Let X represent $10 and Y represent$50
Cashed: X + y = 7
We are given X = Y + 1 or X=y - 1
If X = y + 1 then 2y = 6, y = 3, and X= 4 which means 50*3+10*4 was cashed or 190$was cashed, and 1500 - 190 = 1310$ was lost.
If X = y - 1 then 2y = 8 , y = 4 and X = 3. wjocj 50*4 + 10 *3 was cahsed or 230$was cashed, and 1500 - 230 = 1270$ was lost.
The minimum of this is 1270 hence D.
Director
Joined: 09 Jul 2005
Posts: 595
Followers: 2

Kudos [?]: 57 [0], given: 0

### Show Tags

06 Dec 2005, 03:54
7 checks

1. 4 $10 and 3$50 ---- $190----- he lost$1310

2. 3 $10 and 4$50 ---- $230----- he lost$1270

D is the solution.
Senior Manager
Joined: 03 Nov 2005
Posts: 396
Location: Chicago, IL
Followers: 3

Kudos [?]: 51 [0], given: 17

### Show Tags

07 Dec 2005, 12:34
Agreed. D sounds right
_________________

Hard work is the main determinant of success

Manager
Joined: 05 Nov 2005
Posts: 232
Location: Germany
Followers: 2

Kudos [?]: 70 [0], given: 0

### Show Tags

08 Dec 2005, 00:45
You guys are right D is the OA.
08 Dec 2005, 00:45
Display posts from previous: Sort by